My Physics homework regarding energy/velocity?

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SUMMARY

The discussion focuses on solving a physics homework problem involving energy and velocity of a ball with a mass of 400g falling from a height of 1.5m and rebounding to a height of 1m. The key equations used are Gravitational Potential Energy (GPE = mgh) and Kinetic Energy (KE = 1/2mv²). The initial potential energy is calculated as 6J, which is also the kinetic energy just before impact due to energy conservation. The discussion highlights the need to calculate the velocity at impact and after the rebound, emphasizing the concept of energy loss during the bounce.

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  • Understanding of Gravitational Potential Energy (GPE)
  • Knowledge of Kinetic Energy (KE) equations
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  • Concept of energy conservation in physics
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Hazim1214
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Homework Statement



[If a ball of mass (400g) falls from a height of (1.5m) towards the ground, and rebounds a height of (1m), find:

a) Initial Potential Energy
b) Kinetic Energy of ball before hitting the ground
c) Velocity at which it reaches the ground
d) The velocity at which it leaves the ground
e) Initial Kinetic Energy
f) Energy lost to it's surroundings]

Homework Equations



GPE = mgh
KE = 1/2mv^2 (I think this is relevant..)

and I don't know what else, that's the problem..

The Attempt at a Solution



a) = mgh = .4x10x1.5 = 6J?
b) Final KE = Initial GPE (I think...), so = 6J?
c) v = square root of 37?
d) no idea where to even start..
e) I think this is 0, because it doesn't move initially?
f) no idea where to start...

Anyone able to provide me some insight? Thanks.
 
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Hazim1214 said:

Homework Statement



[If a ball of mass (400g) falls from a height of (1.5m) towards the ground, and rebounds a height of (1m), find:

a) Initial Potential Energy
b) Kinetic Energy of ball before hitting the ground
c) Velocity at which it reaches the ground
d) The velocity at which it leaves the ground
e) Initial Kinetic Energy
f) Energy lost to it's surroundings]

Homework Equations



GPE = mgh
KE = 1/2mv^2 (I think this is relevant..)

and I don't know what else, that's the problem..

The Attempt at a Solution



a) = mgh = .4x10x1.5 = 6J?
Right. It's not moving initially, so all of its energy is potential.
b) Final KE = Initial GPE (I think...), so = 6J?
Right. Energy is conserved during the fall, so the initial potential energy is equal to the final kinetic energy.
c) v = square root of 37?
Not sure where this came from. Show us your calculations.
d) no idea where to even start..
e) I think this is 0, because it doesn't move initially?
You need to work this part the same way you did the first part, but this time you know the final potential energy. For part (e), you're supposed to find the speed the ball is moving as it starts its upward trajectory.
f) no idea where to start...

Anyone able to provide me some insight? Thanks.
After the bounce, it doesn't reach the same height it started at, so what does that tell you about the ball's energy?
 

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