N-D spring-mass damper total energy

Click For Summary
SUMMARY

The discussion focuses on deriving the total energy for an n-dimensional linear spring-mass damper system, specifically using the 1D spring-mass damper equation as a foundation. The participant, ashapi, successfully demonstrates that the total energy is either decreasing or constant by substituting terms from the force equation into the energy derivative. The kinetic and potential energy equations for 2D are presented, and ashapi attempts to generalize these equations for n-D systems, seeking confirmation on the correctness of their approach and guidance on formulating a generalized n-D force equation.

PREREQUISITES
  • Understanding of linear dynamics and Hooke's law
  • Familiarity with differential equations and their applications in physics
  • Knowledge of kinetic and potential energy concepts in multi-dimensional systems
  • Experience with mathematical notation and LaTeX for expressing equations
NEXT STEPS
  • Research the derivation of the n-dimensional spring-mass damper equation
  • Study the principles of energy conservation in multi-dimensional mechanical systems
  • Learn about generalized coordinates and their application in Lagrangian mechanics
  • Explore numerical methods for solving differential equations in n-dimensional systems
USEFUL FOR

Students and professionals in physics and engineering, particularly those focused on mechanical systems, dynamics, and energy analysis in multi-dimensional contexts.

ashapi
Messages
3
Reaction score
0

Homework Statement



I am trying to derive the total energy for an n-dimensional linear (Hookeian) spring-mass damper system and show that the total energy is either decreasing or constant.

Homework Equations


1D spring-mass damper equation
n-D spring-mass damper equation

The Attempt at a Solution



I started with the following force equation in 1D to describe the system:

(1) m\ddot{x} + b\dot{x} + kx = 0

Where:
m\ddot{x} = Facc = m\frac{d^{2}x}{dt^{2}}
b\dot{x} = Fdamp (viscous friction) = C\frac{dx}{dt}
kx = Fpotential (gradient of some potential) = \nablaP(x)

So the equation becomes:

(2) -\nablaP(x) - C\frac{dx}{dt} = m\frac{d^{2}x}{dt^{2}}

I then modeled the total energy as follows:

(3) Etot = P(x) + \frac{1}{2}m\dot{x}2

and

(4) \frac{dE}{dt}= \nablaP(x)\dot{x} + m\dot{x}\ddot{x}

In (4) I substituted m\ddot{x} from (1) and got:

\frac{dE}{dt}= \nablaP(x)\dot{x} + \dot{x}(-\nablaP(x) - C\dot{x})

=> -C\dot{x}2

...which shows that total energy is either decreasing (|\dot{x}| > 0) or constant (\dot{x} = 0)

I then tried to derive the total energy for the n-dimensional case and relate it to an n-D force equation as I did above. To do this I looked at the 2D case and then generalized the formulas for kinetic and potential energy to n-D but I'm not sure if this was correct. Here are my kinetic and potential energy equations for 2D:
 
Physics news on Phys.org
My latex seems to bug out sometimes so if it looks weird please click on the source but let me continue...

KEtot,2D = \frac{1}{2}(m11\dot{x}12 + m22\dot{x}22 + m12\dot{x}1\dot{x}2)PEtot = \frac{1}{2}(m11{x}12 + m22{x}22 + m12{x}1{x}2)

I took the generalized forms to be:

KEtot,nD = \sum_{i=1}^{n} (mii)\dot{x}i2 + \sum_{j=1}^{n-1} \sum_{k=j+1}^n (mjk)\dot{x}j\dot{x}k

...and the same for PE with {x} replacing \dot{x}.

My plan was to take the derivatives of these and replace the m\ddot{x} terms with the force equivalences (as above). Is this right? I also can't think of how to make a generalized form of the force equation for an n-D vector.

Any help would be greatly appreciated.

Thanks,

ashapi
 
Last edited:

Similar threads

Replies
1
Views
2K
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K