1. The problem statement, all variables and given/known data Triangle ABC has A (−1, 3,−3), B (2, 4, 6) and C (3, 0,−5). Use the scalar product to find the angle ACB. No pictures are given 3. The attempt at a solution I have attempted the question by naming the triangle ABC with each angle opposite the line with the same name. The I have changed A B and C into vector equations and used the scalar product between A and B to get the angle C. This does not seem to be working. I end up with -8=√56√19cos(C) c=104.197° This seems like a bit of a crazy answer am I doing it wrong?