- #1
mazz1801
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Homework Statement
Triangle ABC has A (−1, 3,−3), B (2, 4, 6) and C (3, 0,−5). Use the scalar
product to find the angle ACB.
No pictures are given
The Attempt at a Solution
I have attempted the question by naming the triangle ABC with each angle opposite the line with the same name.
The I have changed A B and C into vector equations and used the scalar product between A and B to get the angle C.
This does not seem to be working.
I end up with
-8=√56√19cos(C)
c=104.197°
This seems like a bit of a crazy answer am I doing it wrong?