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Necessary and sufficient condition for inequality

  1. May 27, 2010 #1
    1. The problem statement, all variables and given/known data
    consider two conditions x2-3x-10 < 0 and |x-2| < A on a real number x, where A is positive real number

    (i) find the range of values of A such that |x-2| < A is a necessary condition for x2-3x-10 < 0
    (ii) find the range of values of A such that |x-2| < A is a sufficient condition for x2-3x-10 < 0


    2. Relevant equations



    3. The attempt at a solution
    what is necessary and sufficient condition? I tried googling but found nothing about it...

    thanks
     
  2. jcsd
  3. May 27, 2010 #2
    Well, the first step is to solve the equality x2-3x-10 = 0. You will get two solutions. Then you will have to think about what makes the inequality true. The necessary condition is the one that is requried to make the statement true: "For hot dogs to taste good, they must have mustard". The sufficient condition is the one that says if the condition is met, the statement is true, "As long as hot dogs have mustard, hot dogs are good." The necessary and sufficient condition that if that condition is met, by necessity, the statement is true "only hot dogs that have mustard are good (necessity) and if they have mustard they need nothing else to be good (sufficency)".
     
  4. May 27, 2010 #3
    the answer for the inequality : -2 < x < 5

    then,
    |x-2| < A
    -A < x-2 < A
    2-A < x < 2+A

    I still don't understand how to obtain the necessary and sufficient condition.

    thanks
     
  5. May 27, 2010 #4
    Now think about the other inequality. At x= -2 => |-2-2| = 4 and at x = 5 => |5 - 2| = 3

    The necessary condition is the one that has to be met, though there may be other conditions required to make it true. I will let you work out sufficient.
     
  6. May 27, 2010 #5
    Really??! Not to be contrary (though I usually AM), but you must not have looked too closely. The wikipedia page for "necessary and sufficient conditions" is pretty informative. It requires a bit of logic.

    There are statements P and Q.
    P <=> |x-2| < A
    Q <=> x2-3x-10 < 0

    "Formally, a statement P is a necessary condition of a statement Q if Q implies P."
    Q is equivalent to (x-5)(x+2) < 0, which is equivalent to -2 < x < 5. If you subtract two from each part of the compound inequality, you get
    -4 < x - 2 < 3.
    I guess from here you could say (and it requires a bit of creative insight) that
    -4 < -3 < x - 2 < 3.
    Drop the "-4"
    -3 < x - 2 < 3, which is equivalent to |x-2| < 3.
     
  7. May 27, 2010 #6
    I don't get your hint..don't understand how to relate the examples about x = -2 and x = 5 to find the answer.

    My bad, I meant that I didn't find an example necessary and sufficient condition used directly to inequality. I read the wiki page but I am facing difficulty to apply it to my question.

    I understand your work, but still not be able to translate your work to find the answer...

    Here's my other attempt :
    range of values of A such that |x-2| < A is a necessary condition for x2-3x-10 < 0 is A≥4. Is this right?

    thanks
     
  8. May 27, 2010 #7
    No. Look at the last line of my post and compare it with what you're looking for...
    "|x - 2| < 3" compared with
    "|x - 2| < A".

    What is "A"?
     
  9. May 28, 2010 #8
    A = 3 but the question asks about the range of A so I think the answer won't be just a number.

    My thought :
    |x-2| < A
    -A < x-2 < A
    2-A < x < 2+A

    For : A ≤ 3, the min. value of (2-A) is -1 (not fit to -2 < x < 5)
    For : A ≥ 3, the value of 2-A < x < 2+A can be -1 < x < 5 (not fit to -2 < x < 5)

    So, for -2 < x < 5 fits in 2-A < x < 2+A, A should be at least 4, then A≥4

    Where is my mistake?

    Thanks
     
  10. May 28, 2010 #9
    The absolute value can't be negative, so A has to be >= 0
     
  11. May 28, 2010 #10
    hm...I don't really get what you mean. My answer is A≥4 so it is obvious that A ≥ 0.

    Can you tell me where my mistake is in my work?

    Thanks :smile:
     
  12. May 28, 2010 #11
    Think about it if A were say, 5 what would that imply for what x is? (-3 or 7) Is the original inequality true? (it isn't) Once you have done that thought experiment, would the inequality be right for 3.5? or 2?

    I have found messing with inequalities can be tricky, especially when trying to get signs right. They are often times easier to understand with logic rather than algebra.
     
  13. May 29, 2010 #12
    For the original inequality to be true :
    2-A = -2
    A = 4

    2+A = 5
    A = 3

    there can't be single value for A...

    My logic doesn't work here. I'm very confused..

    Thanks
     
  14. May 30, 2010 #13
    There isn't a singular value, one is the necessary condition the other is the sufficient.
     
  15. May 31, 2010 #14
    Let me try again. So, necessary and sufficient condition are related to 3 or 4.

    necessary condition is the one that is required to make the statement true, then maybe it is the same as my answer before, A ≥ 4.

    sufficient condition is the one that says if the condition is met, the statement is true, then maybe 0 < a ≤ 3.

    Are those right answers?

    Thanks
     
  16. May 31, 2010 #15
    You are almost there, but the inequality for the necessary condition is backwards. Does the concept make sense now?
     
  17. May 31, 2010 #16
    For this one I think I get it. Hope it will be easier for the other questions.

    thanks a lot for your help jamesmo and the chaz :smile:
     
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