Nedd help finding weight over length

  • Context: High School 
  • Thread starter Thread starter slayerus87
  • Start date Start date
  • Tags Tags
    Length Weight
Click For Summary

Discussion Overview

The discussion revolves around calculating the effective weight of a table when lifted at one end at an angle, specifically focusing on the physics of weight distribution and force components. The table weighs 1100 lbs and is 8 ft long, with participants exploring various methods to determine how much weight is supported when lifted at approximately 35 or 40 degrees.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant inquires about the formula to determine the weight supported when lifting one end of a table at an angle.
  • Another participant suggests that the weight supported might be half of the original weight when first lifting one end.
  • It is proposed that if the weight is evenly distributed, the weight on the lifted side decreases as the angle increases, with a minimum weight supported calculated using half the weight times the cosine of the angle.
  • A participant discusses converting the weight to kilograms and calculating the force exerted when lifting at an angle, suggesting the use of force vectors and components.
  • One participant offers a method for calculating the weight shift based on the angle, providing a formula that involves multiplying the angle by a constant and half the weight.
  • Another participant expresses confusion about the calculations and requests assistance in performing the physics involved.
  • A later reply confirms the calculations and discusses the implications of weight shifting, while noting that the table's symmetry and leg weight may affect the results.

Areas of Agreement / Disagreement

Participants express varying levels of understanding and approaches to the problem, with no consensus on a single method or solution. Some agree on the general principle of weight distribution, while others present different calculations and assumptions.

Contextual Notes

Participants mention the need for diagrams and the importance of considering the table's balance and symmetry, indicating that assumptions about these factors may affect the calculations. There are also unresolved mathematical steps and dependencies on specific conditions.

Who May Find This Useful

This discussion may be of interest to individuals studying physics, particularly those focused on mechanics and force analysis, as well as those involved in practical applications of weight distribution in engineering contexts.

slayerus87
Messages
4
Reaction score
0
what i mean is... i need to know how much a table weighs when picked up only at one end

the table is 1100lbs but we are only picking it up (one side only )at about a 35 or 40 degree angle. and also the table is 8 ft long

there's got to be a formula out there but I've been googling for about 30 min now and i havnt found anything

thanks for the help
 
Physics news on Phys.org
i was just thinking, would the weight after lifting be half of the original
 
If the weight is distributed evenly, it is half when you first lift one end. As the angle increases, the amount of weight on the part on the ground increases, though how much depends on how the two sides are supported. The minimum weight the up side needs to support is, irrc, half the weight times the cosine of the angle. You might want to draw a diagram and check that - that's just off the top of my head. The minimum is with the person pushing perpendicular to the table surface (so at an angle when the table is angled to the floor).
 
If we convert 1100 lbs we get approximately 498.9567 kg and then times the Fg which is 9.8 N which equals 4,889.776 N. The you will have to split the problem into a y and x component to get the force the the table exerts when you lift it 35 or 40 degrees up.
 
yes u would haft to use force vectors and x and y components like the guy above me said.
 
thanks a lot guys
 
im sorry about reviving this thread but I am not going to lie to you...i have no idea how to do that. I've googled and tried on my own but i can't teach my self physics


i hate to ask but could someone do this for me:confused:


thank you all so much
 
If we assume the table is perfectly balanced and even then the math is actually pretty easy. The table is usually a 50/50 balance. You need to figure out how much weight is shifted to the other side. Take your angle in degrees (0 for flat, 90 for vertical) multiply by 0.0111... and then multiply half the weight by that to find how much is shifted. Example:
1100 / 2 = 550, that's your normal weight of each side.
40 degrees * 0.0111... = 0.444... * 550 = 244 shifted (306/794).

Again this won't take into account the fact that the legs add weight to the outsides, or if the table is not symmetric.
 
this gave me some trouble 2 would it be sin(40)/(550)=1/x i used law of sines
then x would be (550)/(sin40) oh i see then 244 shifted to the other side that makes sense so it woul be what u said above.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
Replies
4
Views
6K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
13K