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tachu101
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Homework Statement
A 347 kg satellite orbits mercury and makes 6.6 orbits in 1 day.
Mercury ---- Radius 2.44*10^6 meters ----- Mass 3.27*10^23 kg
1.Find the Period of Revolution
2.Calculate the Tangential Velocity
3.Calculate the height above the surface of the planet that the satellite is in orbit
4.Calculate the force of gravity at a distance of 1.50*10^6 meters
Homework Equations
Planetary motion Equations
The Attempt at a Solution
1. Period= 24 hours/6.6 orbits ---- 13090.90909 seconds (per revolution)
2. Tangential Velocity= (2*pi*radius)/Period ----- (2*pi*(2.44*10^6))/13090.90 second ---- Vt= 1171 m/s
3. My friend said that this was the equation for the third part, does anyone know if this is right.
h=((Gravity Constant*Mass Mercury)/Vt^2) - radius of Mercury -----
h=((6.67*10^-11)(3.27*10^23)/1171^2) - 2.44*10^6 meters -----
h= 13465956 meters or 1.3465*10^7 meters (is this right)?
4. Same friend said that the force of gravity would be :
g= (Gravity Constant*Mass Mercury)/((Radius Mercury+Height)^2)
g= (6.67*10^-11)(3.27*10^23)/ ((2.44*10^6+1.5*10^6)^2)
g= 1.405 m/sec^2
Can some one check these answers because I just feel like I did something wrong.