*Need Help: Acceleration and gravity calculation - Thanks

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nukeman
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Homework Statement



This is for a Astronomy class, and I have to go over a few examples. But I need help understand the proper steps in calculating this. I will give you as much information as you can.

I have this formula

"For an object dropped from rest, the distance of fall d is related to the time of fall t and acceleration due to gravity a by

d = 1/2at to the 3rd (the 1/2 is 1 over 2)

If we measure d and t we can solve for the acceleration, a:

a = 2d / t squared (2d / t squared mean over, not divided by)

Now my variables for the calculation are simple.

Distance: 4.42 meters

object drop 1: .707 seconds
objects drop 2: .79 seconds

Can anyone help me?





Homework Equations





The Attempt at a Solution

 
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nukeman said:

Homework Statement



This is for a Astronomy class, and I have to go over a few examples. But I need help understand the proper steps in calculating this. I will give you as much information as you can.

I have this formula

"For an object dropped from rest, the distance of fall d is related to the time of fall t and acceleration due to gravity a by

d = 1/2at to the 3rd you mean t squared[/color]
(the 1/2 is 1 over 2)

If we measure d and t we can solve for the acceleration, a:

a = 2d / t squared
yes
(2d / t squared mean over, not divided by)
same thing) example: 1 'over' 2 is the same as 1 divided by 2)
Now my variables for the calculation are simple.

Distance: 4.42 meters

object drop 1: .707 seconds
objects drop 2: .79 seconds

Can anyone help me?
Are these values determined in a lab experimemt, and you need to calculate 'a', the acceleration due to gravity? They don't look right...
 
your 1st post doesn't make a whole lot of sense if you read back over it. I think you mean d=1/2at^2.
you also don't say what your trying to find out, I assume its gravity(a)
also your meant to have an attempt at solving it before posting.
anyway - very simple put the numbers in your formula and solve for a.
 
whoops posted at the same time and virtually the same thing.