Need Help Doing Integation by Parts

  • Thread starter Thread starter Airp
  • Start date Start date
  • Tags Tags
    Integals parts
Click For Summary

Homework Help Overview

The discussion revolves around finding the integral of the function z^3 e^z^2, specifically using the integration by parts technique. Participants are exploring the challenges associated with this integral and the appropriate application of the integration by parts formula.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants express confusion about how to approach the integral and mention feeling stuck. There are suggestions to analyze the integral using different methods, including u-substitution. Some participants question the validity of certain assumptions regarding the integration process.

Discussion Status

Several participants have shared their attempts and insights, with some offering hints and alternative approaches. There is an ongoing exploration of different strategies, and while no consensus has been reached, the discussion is fostering a collaborative environment for problem-solving.

Contextual Notes

Some participants note the importance of including their work in the discussion rather than relying on images, emphasizing the use of LaTeX for clarity. There is also mention of the need to reconsider certain choices made in the integration process, particularly regarding the selection of u and dv.

Airp
Messages
23
Reaction score
0
Member warned about not showing an attempt

Homework Statement


Find the integral of z^3 e^z^2

Homework Equations


The integration by part formula

The Attempt at a Solution


I have no idea what to do, I'm just turning in circles
 
Physics news on Phys.org
Airp said:

Homework Statement


Find the integral of z^3 e^z^2

Homework Equations


The integration by part formula

The Attempt at a Solution


I have no idea what to do, I'm just turning in circles
Well, show us your latest turn around the circle in working out this integral. You may have overlooked something simple.
 
Some integration by parts problems require using it a few times :D
 
Here's my attempt that doesn't work...
1423589596666-962910281.jpg
 
And another one
1423589706639-37914461.jpg
 
If dv = e^(z^2), v is not e^(z^2)/z^2. You cannot simply reverse the chain rule going backwards because if you take the derivative of that, you'll get something different from the quotient rule.

So when doing parts and one way doesn't work, what to do next?
 
Wel, normally you try going the other way around, but it still doesn't work as shown in the first picture...
 
If you are going to make dv = ez2 dz, then u = z3.

However, it is easier to integrate ez2 dz if you analyze it first using a u-substitution for z2.

Hint: you may not want to make u = z3 for this integral.
 
Oh ok! I think I get now! Thank you to everybody on this thread for your help! I'll try that!
 
  • #10
And when you post again, @Airp, be sure to include at least some of what you have tried.
 
  • #11
This is what I finally did! Thank you again!
14235934962312124757711.jpg
 
  • #12
Also, it's better to include your work right here in the form rather than an image of it. Everything you wrote on paper can be done right here using LaTeX, which isn't really that difficult.

Here is one of the lines from the last image you posted.
$$\frac{z^2e^{z^2}}{2} - \int \frac{2ze^{z^2}dz}{2}$$

The LaTeX script before it is rendered looks like this:
$ $\frac{z^2e^{z^2}}{2} - \int \frac{2ze^{z^2}dz}{2}$ $
Note that I put an extra space between each pair of $ symbols. That prevents the browser from rendering the script.

Fractions: \frac{}{}, with numerator in first pair of braces, and denominator in the second pair
Exponents: Use ^{} after the thing being raised to the power. If the exponent is a single character, the braces aren't needed.
Integrals (indefinite): \int
Integrals (definite): \int_a^b --Here a is the lower limit and b is the upper limit

More info: https://www.physicsforums.com/help/latexhelp/
 
  • #13
Whoa didn't know that thanks!
 

Similar threads

Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K