So t =T1. Why is the acceleration 2a in the second equation?
and m1 distance double m2 distance that`s why the acceleration proportion is 2:1
is that right ?
No that's not correct where did you get that idea?
can you be more specific , what is not correct and how to solve the problem ?
I don't see anything wrong with your equations. Solve them to find a.
t-m_1gsin30=m_1*2a \ *2
m_1=m_2 = 5kg
2t - 2t - 2*5*0.5g + 5g= 20a+5a
0=25a ====> ??????????????
the answer in the book is a=2.8
how is that ????
plzz help .
Oops. It looks like the masses are in equilibrium if they are equal. Are you sure you have the masses correct? (Also, what book are you using?)
yea i am sure .
the book is classical mechanics by yoram eshel .
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