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****PICTURE ATTACHED AT BOTTOM****

## Homework Statement

The current in the 13.8-Ω resistor in the attached picture is .795 A. Find the current in the other resistors in the circuit.

## Homework Equations

V=RI

In a series circuit:

V of Circuit = V1 + V2 + V3 +...Vn

I of Circuit = I1 = I2 = I3 = ...In

R of Circuit = R1 + R2 + R3 +... Rn

In a parallel circuit:

V of Circuit = V1 = V2 = V3 = ... Vn

I of Circuit = I1 + I2 + I3 +... In

1/R of Circuit = 1/(R1) + 1/(R2) + 1/(R3) +... 1/(Rn)

## The Attempt at a Solution

For the 13.8-Ω resistor, I found that Voltage = 10.971 by using V=IR

- Because V of Circuit = (V1 = V2 = V3 = ... Vn), the Voltage for the 17.2-Ω resistor is also 10.971

--Based on this, the Current for the 17.2-Ω resistor is .638:

V=IR

I=V/R

I=(10.971)/(17.2)

I=.638

After this, I proceeded to find the equivalent resistance for the entire circuit.

To find this, I separated the circuits into groups.

Group 1= the 15-Ω and 12.5-Ω resistors (they are in series).

Group 2= the 13.8-Ω and 17.2-Ω resistors (they are parallel).

Group 3= the 8.45-Ω and 4.11-Ω resistors (they are in series).

When solved for, the equivalent resistance for each group is as follows:

Group 1= 27.5-Ω

Group 2= 7.66-Ω

Group 3= 12.56-Ω

Note that Groups 2 and 3 are now parallel. We will combine them into Group 4.

Group 4 Resistance = 4.75-Ω

Now we only have Groups 1 and 4 left in series. When combined, we will get the net resistance for the entire Circuit. This works out to be 32.56-Ω

.....So that's everything I could find, which is decent, but doesn't come anywhere near answering the question. I know I must be missing something somewhere.

How do I figure out the individual currents for each resistor with the information I currently have?