Need Help with Homework? Solve Two Physics Problems with Expert Guidance

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Homework Help Overview

The discussion revolves around two physics problems involving wave propagation in a string and the motion of a stone dropped into a well. The first problem involves calculating the time it takes for a wave pulse to travel along a string with specific masses and dimensions. The second problem concerns determining the depth of a well based on the time taken for a stone to fall and the sound of the splash to be heard.

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Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the relationship between mass, tension, and wave speed in the first problem. Questions arise about the setup and the effect of the masses on the string. For the second problem, there is a suggestion to break it down into two parts and to consider kinematic equations, as well as the speed of sound in air at a given temperature.

Discussion Status

Some participants are seeking clarification on the first problem and suggest the need for a diagram. Others are exploring the implications of the forces acting on the string and how to approach the second problem methodically. There is no explicit consensus, but various lines of reasoning and hints have been provided to guide the discussion.

Contextual Notes

Participants note the importance of understanding the parameters affecting wave speed and the need to account for multiple unknowns in the second problem. The discussion reflects a collaborative effort to clarify concepts and approaches without providing direct solutions.

ukpclark
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Need some Homework help PLEASE

1. Homework Statement (problem one i need help with)

A light string of mass 10.0 g and length L = 3.00 m has its ends tied to two walls that are separated by the distance D = 1.90 m. Two masses, each of mass m = 1.95 kg, are suspended from the string as in Figure P13.64. If a wave pulse is sent from point A, how long does it take to travel to point B?
Diagram is attached

I think you apply Newtons second law for equilibrim applied to the block and mass per unit length of the string is =M/L
Sqaure root of (1.95kg)(9.8m/s^2)/(10g)(1.90m)=62.6m/s

t=d/v=1.90m/62.6m/s


Problem 2 i need help with.

A stone is dropped from rest into a well. The sound of the splash is heard exactly 2.20 s later. Find the depth of the well if the air temperature is 12.0°C.

I have completed the rest of my webassign but i am completely lost on these two problems. I have pages of notes trying to solve the first problem but and totally lost on the second. Thanks so much.
 

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I think I need to see a diagram for #1 and work on both problems before I know how I can help you.
 
Hey, I'm assuming in your first problem a mass is hung from each side of the string? If so, think about what determines the speed of a pulse or wave in a given medium; that is, is determined by the force acting on the medium, or is it a parameter of the medium? What do the masses on the end of the string do to the string?

The second problem is best tackled in two parts. It is helpful to write out which equations you have at your disposal (in this case, the kinematic equations for motion in one dimension) and how many unknowns you're working with. If there are two unknowns, you'll need two separate expressions relating these two unknowns. As a hint, the speed of sound at varying temperatures can be found in your textbook.

Hope this helps.
 
ukpclark said:
I think you apply Newtons second law for equilibrim applied to the block and mass per unit length of the string is =M/L
Sqaure root of (1.95kg)(9.8m/s^2)/(10g)(1.90m)=62.6m/s

You have to find the tension in the string joining the two masses, and then apply the formula for speed of wave.

ukpclark said:
A stone is dropped from rest into a well. The sound of the splash is heard exactly 2.20 s later. Find the depth of the well if the air temperature is 12.0°C.

If t is the time for the stone to fall, then h = (1/2)gt^2. Now find the time for the sound to travel distance h in time (2.2 - t), and eliminate t to find h.
 

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