- #1

bigbuck

- 6

- 0

A solid disk with m=60.0kg and a diameter of 48.0cm is to be turned from rest through 12.0 revolutions in 6.00s. Calculate the torque required to accomplish this.

What ive got is this:

Tau=I*al(angular acceleration)

I=.5*m*r^2 .5*60.0kg*.240m^2=1.728kg*m^2

Al = om/t (convert to om and then to al)12revs/6sec=2.00revs/sec = 12.56rads/s / 6

sec = 2.09 rads/s^2=al

1.728kg*m^2 * 2.09rads/s^2= 3.61N*m ...is this right?

This is an online physics course and I am getting a little lost at this point. The course notes are vague at best and I am just not sure if i have the irght answers or not.

ANy help would be appreciated.