Need Help with Integrating (e^(-x)sin(x))? Find the Solution Here!"

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Homework Help Overview

The discussion revolves around finding the integral of the function (e^(-x)sin(x)) over the limits from 1 to 2. The problem falls within the subject area of calculus, specifically focusing on integration techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts integration by parts and expresses confusion about the next steps after their initial calculations. Some participants suggest reconsidering the choice of functions used in the integration by parts process, while others provide references to similar problems for further exploration.

Discussion Status

The discussion is ongoing, with participants offering guidance on the integration technique and suggesting a reevaluation of the approach taken by the original poster. There are multiple interpretations of the integration process being explored, but no explicit consensus has been reached.

Contextual Notes

Participants are discussing the use of integration by parts and the choice of functions within that method. There is an acknowledgment of potential confusion regarding the application of the technique.

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Homework Statement


what is the integral of (e^(-x)sin(x)) with limits 2 and 1


Homework Equations





The Attempt at a Solution



let the integral be denoted as I
i used integration by parts twice and i got that:
I=[-e^(-x)(sin(x))] + [e^(-x)(sin(x))] + I

i'm stuck now and don't know what to do, can someone help me please.
thank you very much
 
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That's perfectly valid, but not very interesting. I think you used the wrong 'part' for one of your integrations by parts. In udv=d(uv)-vdu, you can use either the trig function or the exponential for v. In one integration you used the exponential and in the other the trig. Use the same one for both.
 
First off, we get:
I=-e^{-x}\sin(x)|^{x=2}_{x=1}+\int{e}^{-x}\cos(x)dx
Continue to use e^{-x} as u' in the integration by parts formula.
 
thanx 2 all
;) ;) ;)
 

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