Need quick help with these perms/coms questionscheck answers

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SUMMARY

The discussion addresses the combinatorial problem of selecting a cricket selection committee from 5 former batsmen and 3 former bowlers. The total number of ways to form a committee of 4 members that includes at least one former batsman is calculated to be 70. Additionally, the requirement for at least one batsman and one bowler reduces the total combinations to 65 by subtracting the cases where no batsman or bowler is included. The participants confirm that using the binomial coefficient 8C4 simplifies the calculations.

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[SOLVED] Need quick help with these perms/coms questions..check answers

Homework Statement


A cricket selection committee of 4 members is to be chosen from 5 former batsmen and 3 former bowlers.

In how many ways can this committee be selected so that the committee includes at least

1)One former batsman
2) One batsman and one bowler.


Homework Equations





The Attempt at a Solution



B=Batsman
b=bowlers

1)At least one former batsman

1B 3b=5C1*3C3=5
2B 2b=5C2*3C2=30
3B 1b=5C3*3C1=30
4B 0b=5C4=5

total=70 ways

2) no. of way to select without any restriction=8C4=70

so for at least one B and one b, it is 70-5=65


Also,since in part 1,those are the only ways to make the selection...does that mean I could have just said 8C4 instead of writing out all the ways?
 
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Yes to all of the above, I think.
 
well then...great...! I got confused since all of that was 8 marks
 

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