Need to determine distance maximizing angle theta.

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SUMMARY

The discussion focuses on determining the optimal distance (X) from a movie screen to maximize the viewing angle (theta) in a geometry problem. The screen is positioned 9 feet above the ground and is 16 feet tall. Participants suggest using trigonometric relationships, specifically cotangent and tangent functions, to derive theta as a function of X. The key equations involve cot(alpha) = x/9 and tan(theta + alpha) = 25/x, leading to the conclusion that finding the derivative d(theta)/dx and setting it to zero will yield the maximum angle.

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Homework Statement



A movie screen at the front of a room is 9 feet above the ground and 16 feet tall. Determine the distance X you must sit away from the screen in order to maximize your viewing angle.

[ I tried to make the picture :P. I need to find X]

http://img50.imageshack.us/img50/2781/probwk6.png The little fish thing is i believe alpha...i don't know the Greek name for that.

Homework Equations



Well i figured that i need to do the tangent of both triangles and set them equal to each other, but i am confused if i need to take into account the second triangle for tan of theta.

I am coming up empty handed, and what i got was 25/tan[theta] but i don't think its right.
 
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help...anyone? i kinda need desperate help :P
 
Good drawing! And, yes, that Greek letter is alpha.

What you need is an equation with theta as a function of x.

First, let's take care of alpha: cot(alpha) = x/9, so alpha = cot^(-1)(x/9).

Next, let's get a relationship between the larger angle and x.

tan(theta + alpha) = 25/x
so theta + alpha = tan^(-1)(25/x)

But we already have alpha, so you should be able to get theta as a function of x; i.e., theta = f(x).

Now, do the usual and find d(theta)/dx and set it equal to 0.

Does that get you started?
 

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