Need to get an equation for when it is tangent

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To determine the equation of a sphere tangent to the yz-plane and the line y=7, the center point (3, -1, -2) is crucial. The general formula for a sphere is (x - h)² + (y - k)² + (z - l)² = r², where (h, k, l) is the center and r is the radius. For tangency to the yz-plane, the x-coordinate must equal the radius, leading to the equation x = 3 for tangency. To find the radius, the distance from the center to the tangent point on the yz-plane must be calculated, which is simply the x-coordinate of the center. Understanding these relationships allows for the correct formulation of the sphere's equation.
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I need someone to help me! i have been given a center point of (3,-1,-2) of a sphere and i need to get an equation for when it is tangent to the a) the yz plane b) y=7. i know i need to use the distance formuala to attain the radius, but i am majorly confusing myself in what coordinate to pick. Do i just use (0,0,0) as tangent point to the plane for a)?? please help!
 
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What is the general formula for a sphere?
 
what i have so far is (x-3)^2 + (x+1)^2 + (x+2)^2= r^2. i just need to find the radius of this equation, so that the sphere will be tangent to the yz plane. once i know the coordinates to use for the tangent point, i can use the distance formula to give me the radius.
 
It would actually be ...

(x-3)^2+(y+1)^2+(z+2)^2=r^2

If you want it tangent to the yz-plane, what variable must be 0?
 
that is what i meant..sorry. i still need to know what the equation would be though to figure out when it is tangent to the yz plane.
 
So you want a single point to be on the yz plane. What is the equation of the yz plane?
At what point of the sphere is that equation true? What is the distance between that point and the center of the sphere?
 

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