Negate "f has limit L at c": f does not have limit L at c

AI Thread Summary
The discussion focuses on negating the statements regarding limits and continuity of a function f at a point c. It clarifies that f does not have limit L at c if there exists an epsilon greater than zero such that for any sequence converging to c, the difference |f(x_n) - L| remains greater than epsilon. Additionally, f is not continuous at c if there exists an epsilon such that for some sequence converging to c, |f(x_n) - f(c)| is greater than epsilon. The negation of "f has a limit at c" is simply "f does not have a limit at c." Overall, the discussion emphasizes the definitions and implications of limits and continuity in relation to sequences.
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I found this in another threat
however i do not know wat he means by convergent sequences. Is something like when u trying to take the limit at an ASYMPTOTE of a fuction? i know that the limit doesn't not exist( or goes to infinitive i cannot recall) is that wat he means by convergent sequence?

Let f:I->R and let c in I. I want to negate the statements: "f has limit L at c" and "f is continuous at c". Are these correct?

f does not have limit L at c if there exists e>0 such that for some sequence {x_n} converging to c, |f(x_n)-L|>e for every n.

f is not continuous at c if there exists e>0 such that for some sequence {x_n} converging to c, |f(x_n)-f(c)|>e for every n.

edit: also, what is the negation of "f has a limit at c"?
 
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the negation of "f has a limit at c" is "f does not have a limit at c". (meaning there is no L such that blah blah)

for the one about the sequence f is not continuous at c if for some x in I, \lim_{x\rightarrow c}f(x) \neq f(c). that is... well you know the definiton of limit, & if not it's in your book. of course if there's one x where f isn't continuous then if isn't continuous on the domain.
 
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