Net Electric Field Defined at a Point with Charges Present

Click For Summary
SUMMARY

The discussion centers on the definition of the electric field (\(\vec{E}\)) at a point where charges are present, specifically in the context of Gauss's Law, expressed as \(\nabla \cdot \vec{E} = \frac{\rho}{\epsilon_{0}}\). Participants clarify that a test charge, defined as having a vanishingly small charge, can be introduced without interfering with the ambient electric field. They emphasize that a charge does not exert a net electric force on itself, and when calculating the electric field due to a charge distribution, only the fields from surrounding charges are considered. The conversation also touches on the concept of macroscopic versus microscopic electric fields in matter, as discussed in Griffiths' "Introduction to Electrodynamics".

PREREQUISITES
  • Understanding of Gauss's Law in electromagnetism
  • Familiarity with electric field concepts and definitions
  • Knowledge of charge distributions and their implications in classical electrodynamics
  • Basic grasp of macroscopic versus microscopic electric fields
NEXT STEPS
  • Study Griffiths' "Introduction to Electrodynamics" for detailed explanations on electric fields and charge distributions
  • Explore the concept of macroscopic average density of charge and its implications in electric field calculations
  • Learn about the derivation of electric fields inside solid spheres using Gauss's Law
  • Investigate the differences between classical and quantum electrodynamics regarding charge interactions
USEFUL FOR

Students and professionals in physics, particularly those focusing on electromagnetism, electrical engineers, and anyone interested in the theoretical foundations of electric fields and charge interactions.

pardesi
Messages
337
Reaction score
0
consider a region where charge is distributed then we have by gauss' law
\nabla \cdot \vec E =\frac{\rho}{\epsilon_{o}}
what is \vec E here.if it is the net electric field then how is that the field is defined at a point where charges are itself present
 
Last edited by a moderator:
Physics news on Phys.org
pardesi+edits said:
consider a region where charge is distributed then we have by gauss' law
\nabla \cdot \vec E =\frac{\rho}{\epsilon_{o}}
what is \vec E here.if it is the net electric field then how is that the field is defined at a point where charges are itself present


The electric field is defined as the force/charge ratio on a small "test charge", see for instance

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elefie.html
 
so how come u introduce a test charge at a place where ther i s already presence of charge
 
Electric and Magnetic fields in matter are the macroscopic fields ... which means the average over regions large enough to contain many atoms ... The actual microscopic fields will fluctuate strongly inside matter ...

This is what I understand from Griffiths.
 
pardesi said:
so how come u introduce a test charge at a place where ther i s already presence of charge

because by definition a test charge's charge is vanishingly small. you need this to argue that the field of the charge itself doesn't interfere with the ambient field at that point.
 
ice109 said:
because by definition a test charge's charge is vanishingly small. you need this to argue that the field of the charge itself doesn't interfere with the ambient field at that point.

I think what the issue is trying to get at is that if we calculate the electric field of a charge distribution in matter then what happens to E at the exact position where we have the charge (just based on classical electrodynamics).
 
Last edited:
A charge does not exert a net electric force on itself. Otherwise a charge could set itself in motion by way of its own electric field. Therefore, when calculating the electric force on a particular charge, we include only the fields produced by the other surrounding charges.

ansrivas said:
if we calculate the electric field of a charge distribution in matter then what happens to E at the exact position where we have the charge

An infinitesmal piece of the charge distribution does not exert an electric force on itself. However, the remainder of the charge distribution does. A distribution of (say) positive charge flies apart by mutual repulsion unless there are other forces holding it together.
 
Last edited:
ansrivas said:
I think what the issue is trying to get at is that if we calculate the electric field of a charge distribution in matter then what happens to E at the exact position where we have the charge (just based on classical electrodynamics).
yes this is my question and not whether the charge exerts force on itself or not.
if we have a continious charge distribution then hoe is that w e find the net field at a point(what is the charge we have to leave out)
 
jtbell said:
An infinitesmal piece of the charge distribution does not exert an electric force on itself. However, the remainder of the charge distribution does. A distribution of (say) positive charge flies apart by mutual repulsion unless there are other forces holding it together.


I tried to be clear that we are not talking about test charges here at all. The issue is we all know that charge is quantized. So what does one exactly mean by volume density of charge. This is made clear by the question here where we are discussing the field at the very point we have an electron sitting. So as I said without getting into Quantum effects what does classical electrodynamics have to say about this.

So a charge distribution having a volume density \rho is really a macroscopic average density and the electric field that we calculate can only be a macroscopic average. The field calculated using a volume distribution cannot be expected to be uniform in the tiniest scale. This is an idealization to enable ease of calculation.

Griffiths talks about this exact problem in his book "Intro. to electrodynamics". Just look for "macroscopic" in the index if you have the book.
 
  • #10
yes exactly that's what my point is also another question .any book has a derivation of a field inside a solid sphere by using gauss's law on a concentric sphere .But what's the meaning of field inside the sphere .yes one could argue that if we remove some charge and then calculate the field the'r but will that give u the actual net field it does but how do we know that .
for ex had that distribution be surface charge clearly we would have got only half of our desired value
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
739
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
437
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 29 ·
Replies
29
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K