Net Entropy Change in Heat Engine Cycle

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Homework Help Overview

The discussion revolves around a heat engine operating between two temperature reservoirs, specifically analyzing the net change in entropy during its cycle. The original poster presents calculations involving heat absorbed from the high-temperature reservoir and work done, seeking clarification on the entropy changes associated with the working fluid and the reservoirs.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculations of heat transfer and work done, questioning the implications of these values on the entropy changes of the working fluid and the reservoirs. Some participants express uncertainty about how the cyclic nature of the engine affects entropy.

Discussion Status

The conversation includes attempts to clarify the relationship between the heat engine's operation and the changes in entropy for both the working fluid and the reservoirs. There is acknowledgment of differing interpretations regarding the total entropy change, with some participants suggesting that the original calculations may be correct but lacking in fundamental understanding.

Contextual Notes

Participants are navigating the complexities of thermodynamic principles, particularly regarding the definitions of entropy changes in cyclic processes and the roles of the hot and cold reservoirs. There is a mention of potential confusion surrounding the concept of reversible versus irreversible processes.

Sondra
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Homework Statement


A heat engine operates between a high-temperature reservoir at 634 K and a low-temperature reservoir at 320 K. In one cycle, the engine absorbs 6540 J of heat from the high-temperature reservoir and does 2200 J of work.

Homework Equations


What is the magnitude of the net change in entropy as a result of this cycle?

The Attempt at a Solution


Qh=6540J
W=2200J
Find Qc=Qh-W=4340J
Sc=Qc/Tc= 4340J/320K=13.56J/K
Sh=Qh/Th= 6540J/634K= 10.32 J/K
Net S= Sc-Sh= 3.2 J/K
Please help. I feel like i am doing this problem correctly but I seem to be missing something. Thank you!
 
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Sondra said:

Homework Statement


A heat engine operates between a high-temperature reservoir at 634 K and a low-temperature reservoir at 320 K. In one cycle, the engine absorbs 6540 J of heat from the high-temperature reservoir and does 2200 J of work.

Homework Equations


What is the magnitude of the net change in entropy as a result of this cycle?

The Attempt at a Solution


Qh=6540J
W=2200J
Find Qc=Qh-W=4340J
Sc=Qc/Tc= 4340J/320K=13.56J/K
Sh=Qh/Th= 6540J/634K= 10.32 J/K
Net S= Sc-Sh= 3.2 J/K
Please help. I feel like i am doing this problem correctly but I seem to be missing something. Thank you!
Since the engine is operating in a cycle, what is the change in entropy of the working fluid?
What is the change in entropy of the hot reservoir? What is the change in entropy of the cold reservoir? What is the total change in entropy of the working fluid and the two reservoirs?

Chet
 
Chestermiller said:
Since the engine is operating in a cycle, what is the change in entropy of the working fluid?
What is the change in entropy of the hot reservoir? What is the change in entropy of the cold reservoir? What is the total change in entropy of the working fluid and the two reservoirs?

Chet
So the hot reservoir has a net (-) charge because it's energy is absorbed. The net change in the cold is (+) because work is being put into the system and needs to be exhausted..? I am not exactly sure of how a "cycle" would influence the entropy unless it is referring to a reversible engine.
 
Sondra said:
So the hot reservoir has a net (-) charge because it's energy is absorbed. The net change in the cold is (+) because work is being put into the system and needs to be exhausted..? I am not exactly sure of how a "cycle" would influence the entropy unless it is referring to a reversible engine.
In any cycle, the change in any state function (like entropy), for a system experiencing the cycle, is equal to zero. The hot reservoir loses heat to the engine and the cold reservoir receives heat from the system. So, the change in entropy of the hot reservoir is negative and the change in entropy of the cold reservoir is positive.

Chet
 
Chestermiller said:
In any cycle, the change in any state function (like entropy), for a system experiencing the cycle, is equal to zero. The hot reservoir loses heat to the engine and the cold reservoir receives heat from the system. So, the change in entropy of the hot reservoir is negative and the change in entropy of the cold reservoir is positive.

Chet
The correct answer is not zero :/
 
Sondra said:
The correct answer is not zero :/
I didn't say it was. I said that the entropy change of the working fluid is zero. The total entropy change, including the reservoirs, is not zero. Your original answer was correct, although you obtained this answer without understanding what is happening fundamentally. I was trying to explain the correct way to analyze the problem.

Chet
 
Last edited:
Chestermiller said:
I didn't say it was.
So yeah I understand the Sh is negative that is why i subtracted it from the positive Sc. Is my equation incorrect?
 

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