Net External Force in a Direction

Click For Summary
SUMMARY

The net external force in the x direction for the crate is calculated by subtracting the force to the right (92.3 N) from the force to the left (116.8 N). The correct calculation is 116.8 N - 92.3 N, resulting in a net external force of 24.5 N to the left. The discussion emphasizes that the same method used for the y-direction can be applied to the x-direction, reinforcing the principle of vector subtraction in physics.

PREREQUISITES
  • Understanding of vector forces
  • Basic knowledge of Newton's laws of motion
  • Familiarity with force units (Newtons)
  • Ability to perform basic arithmetic operations
NEXT STEPS
  • Study vector addition and subtraction in physics
  • Learn about net force calculations in two dimensions
  • Explore Newton's second law of motion
  • Review examples of force diagrams and free-body diagrams
USEFUL FOR

Students studying physics, particularly those learning about forces and motion, as well as educators seeking to clarify concepts related to net external forces.

Smiley.Teddy
Messages
1
Reaction score
0

Homework Statement


A crate is pulled to the right with a force of 92.3 N, to the left with a force of 116.8 N, upward with a force of 508.8 N, and downward with a force of 248. 6 N
What is the net external force in the x direction? Answer in units of N




Homework Equations


When I solved for the Y-Direction I simply subtracted the upward force from the downward force and got the answer correct. I don't know what to do for the x-direction.



The Attempt at a Solution


X direction: I attempted these:
-92.3N-116.8N = -209.1
116.8N-92.3N = 24.5
116.8N^2+92.3N^2 and then square root that answer to get = 148. 867...

Please help me understand what it is that I'm doing wrong. Thank you. =]
 
Physics news on Phys.org
Welcome to PF!

Hi Smiley.Teddy ! Welcome to PF! :smile:
Smiley.Teddy said:
A crate is pulled to the right with a force of 92.3 N, to the left with a force of 116.8 N, upward with a force of 508.8 N, and downward with a force of 248. 6 N
What is the net external force in the x direction? Answer in units of N

When I solved for the Y-Direction I simply subtracted the upward force from the downward force and got the answer correct. I don't know what to do for the x-direction.

(why did you think they might be different? :confused:)

For the x-direction, just do exactly what you did for the y-direction. :smile:
 

Similar threads

Replies
6
Views
2K
Replies
8
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
4
Views
2K
Replies
20
Views
2K