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Net External Force in a Direction

  1. Nov 19, 2008 #1
    1. The problem statement, all variables and given/known data
    A crate is pulled to the right with a force of 92.3 N, to the left with a force of 116.8 N, upward with a force of 508.8 N, and downward with a force of 248. 6 N
    What is the net external force in the x direction? Answer in units of N

    2. Relevant equations
    When I solved for the Y-Direction I simply subtracted the upward force from the downward force and got the answer correct. I don't know what to do for the x-direction.

    3. The attempt at a solution
    X direction: I attempted these:
    -92.3N-116.8N = -209.1
    116.8N-92.3N = 24.5
    116.8N^2+92.3N^2 and then square root that answer to get = 148. 867...

    Please help me understand what it is that I'm doing wrong. Thank you. =]
  2. jcsd
  3. Nov 20, 2008 #2


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    Welcome to PF!

    Hi Smiley.Teddy ! Welcome to PF! :smile:
    (why did you think they might be different? :confused:)

    For the x-direction, just do exactly what you did for the y-direction. :smile:
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