# Net External Force in a Direction

1. Nov 19, 2008

### Smiley.Teddy

1. The problem statement, all variables and given/known data
A crate is pulled to the right with a force of 92.3 N, to the left with a force of 116.8 N, upward with a force of 508.8 N, and downward with a force of 248. 6 N
What is the net external force in the x direction? Answer in units of N

2. Relevant equations
When I solved for the Y-Direction I simply subtracted the upward force from the downward force and got the answer correct. I don't know what to do for the x-direction.

3. The attempt at a solution
X direction: I attempted these:
-92.3N-116.8N = -209.1
116.8N-92.3N = 24.5
116.8N^2+92.3N^2 and then square root that answer to get = 148. 867...

Please help me understand what it is that I'm doing wrong. Thank you. =]

2. Nov 20, 2008

### tiny-tim

Welcome to PF!

Hi Smiley.Teddy ! Welcome to PF!
(why did you think they might be different? )

For the x-direction, just do exactly what you did for the y-direction.