Net Force acting on block on incline

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The problem involves a 6.50 kg block on an incline with an angle of 18.8° and static and kinetic friction coefficients of 0.685 and 0.485, respectively. Since the block is at rest, the net force acting on it is zero. The calculation confirms that with no acceleration, the net force equals mass multiplied by acceleration, resulting in F = 0. This indicates that static friction is sufficient to prevent the block from sliding down the incline. The conclusion is that the net force acting on the block is indeed zero.
TheFlemster
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Homework Statement


A 6.50 kg block is placed on an inclined surface. The coefficients of static and kinetic friction between the block and the surface are 0.685 and 0.485, respectively. The incline makes an angle of 18.8° relative to horizontal. The block is at rest and remains at rest. What is the magnitude of the net force that acts on the block?

Homework Equations


net Force, F = ma

The Attempt at a Solution


F = ma
F = mass * acceleration
F = mass * 0
net Force, F=0
 
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Exactly right. Good.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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