Net force and Newton's laws of motion!!! 1. The problem statement, all variables and given/known data A barge is hauled along a straight-line section of canal by two horses harnessed to tow ropes and walking along the tow paths on either side of the canal. Each horse pulls with a force of 490 N at an angle of 19° with the centerline of the canal. What is the net force on the barge? 2. Relevant equations Fx= F1x + F2x..... Fy= F1y + F2y.... Fnet 3. The attempt at a solution I broke it into components and got the following: F1x= 490cos19 F2x=490cos19 F1y=490sin19 F2y=490sin19 I'm not too sure where to go from here. I think you add all the Fx components and Fy components, then square them and take the square root but when I tried that, I got it wrong, which was 980 N (and they do not give you the correct answer). Any help will be appreciated!!