net force exerted on the system quick question- halllp lol. 1. The problem statement, all variables and given/known data The vector position of a 3.10 g particle moving in the xy plane varies in time according to the following equation. r1 = (3i+3j)t + 2jt^2 At the same time, the vector position of a 5.15 g particle varies according to the following equation. r2= 3i-2it^2 -6jt For each equation, t is in s and r is in cm. Solve the following when t = 2.00 (e) Find the net force exerted on the two-particle system. i μN j μN 2. Relevant equations f=ma 3. The attempt at a solution Took the 2nd derivative to get the acceleration vectors. r1 : 4 j (mass is 3.1g) r2 : -4 i (mass is 5.15g) I tried this: ( (m2)(4 i) ) / (m1 + m2) and got -1.93515 in the i-hat direction. It is incorrect : "Your answer is off by a multiple of ten."