The vector position of a 3.15 g particle moving in the xy plane varies in time according to the following equation.
r1 = (3i+3j)t + 2jt^2
At the same time, the vector position of a 5.00 g particle varies according to the following equation.
r2= 3i-2it^2 -6jt
For each equation, t is in s and r is in cm. Solve the following when t = 2.50:
(a) Find the vector position of the center of mass.
(b) Find the linear momentum of the system.
(c) Find the velocity of the center of mass.
(d) Find the acceleration of the center of mass.
(e) Find the net force exerted on the two-particle system.
im really not sure about this
i think for some of them you would use p=mv
and for the center of mass you use 1/M integral of r??
The Attempt at a Solution
im not sure what to do first
am i plugging in for t first? and then what do i do?