Motion of a system of particles

In summary, the center of mass for a system of two particles moves according to the following equations: -R1 = (3i+3j)t + 2jt^2-R2= 3i-2it^2 -6jtFor each equation, t is in s and r is in cm. At time t = 2.50, the center of mass for the system is found according to the following equation: (a) Find the vector position of the center of mass.(b) Find the linear momentum of the system.(c) Find the velocity of the center of mass.(d) Find the acceleration of the center of mass.(e
  • #1
physics_geek
84
0

Homework Statement


The vector position of a 3.15 g particle moving in the xy plane varies in time according to the following equation.
r1 = (3i+3j)t + 2jt^2


At the same time, the vector position of a 5.00 g particle varies according to the following equation.
r2= 3i-2it^2 -6jt

For each equation, t is in s and r is in cm. Solve the following when t = 2.50:
(a) Find the vector position of the center of mass.

i cm
j cm

(b) Find the linear momentum of the system.
i g-cm/s
j g-cm/s

(c) Find the velocity of the center of mass.
i cm/s
j cm/s

(d) Find the acceleration of the center of mass.
i cm/s2
j cm/s2

(e) Find the net force exerted on the two-particle system.
i μN
j μN


Homework Equations


im really not sure about this
i think for some of them you would use p=mv
and for the center of mass you use 1/M integral of r??


The Attempt at a Solution


im not sure what to do first
am i plugging in for t first? and then what do i do?
 
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  • #2
Yes you will need to evaluate the vector function at the time given and determine position.

Basically your center of mass is a function of the motion of both particles, so you will need to develop the answers from the vector form of the Center of Mass equation.

The acceleration will let you find the net force by ordinary means.
 
  • #3
ok I am still a bit confused
so i plug in the value of t into both equations and then what..im not getting it right
 
  • #4
OK, for the first one you have the values of R1 and R2 @ t=2.5 in terms of i,j.

The weighted average of their positions then means that you multiply each by the mass of the appropriate particle and then divide by the total mass of the particles. These are all scalar operations on the i,j dimensions of each vector @ 2.5.
 
  • #5
o so by doing this
it'll give me the vector position of each?
 
  • #6
physics_geek said:
o so by doing this
it'll give me the vector position of each?

Each R vector is a function in t.

But at any t, you have a value for R, and hence the displacement vector for each particle.

You are simply evaluating the vector at that time and applying the rules for determining the center of mass.
 
  • #7
oo so by evaluating each at t..then i just multiply by the masses
and add them up..and then divide everything by the total mass?
 
  • #8
physics_geek said:
oo so by evaluating each at t..then i just multiply by the masses
and add them up..and then divide everything by the total mass?

Yes, that's what the center of mass is.

In this case though they give you the i,j components, but they can be dealt with independently.
 
  • #9
nevermind- just added the vectors
 
Last edited:
  • #10
(e) Find the net force exerted on the two-particle system.
i μN
j μNShouldn't the net force exerted for i and j just be the :

acceleration i-hat * (m1 + m2)
and
acceleration j-hat * (m1 + m2)

I have part D for acceleration as
r1 : 4 j
r2 : -4 i

I'm doing this and am getting the wrong answer.
 
  • #11
bump for question due today.
 
  • #12
so i figured out the vector position of the center of mass

now I am trying to find the velocity of the center of mass
i have no idea how to do this..i know its going to be P/M but how do i get the velocities?
 
  • #13
take the derivative of the position vectors and to find the velocity vectors.
 
  • #14
yea i figured it out
thanks a lot guys for your help :)
 

1. What is the difference between linear and rotational motion?

Linear motion is when a system of particles moves in a straight line, while rotational motion is when a system of particles moves around an axis.

2. How is the center of mass related to the motion of a system of particles?

The center of mass is the point at which the entire mass of a system of particles can be considered to be concentrated. The motion of the center of mass is affected by the external forces acting on the system.

3. What is the equation for calculating the momentum of a system of particles?

The equation for calculating the momentum of a system of particles is p = mv, where p is the momentum, m is the mass of the system, and v is the velocity of the system.

4. How does the conservation of momentum apply to a system of particles?

The conservation of momentum states that the total momentum of a system of particles remains constant, as long as there are no external forces acting on the system. This means that the initial momentum of the system is equal to the final momentum of the system.

5. Can the motion of a system of particles be affected by internal forces?

Yes, the motion of a system of particles can be affected by both external and internal forces. Internal forces are forces that act between particles in the system, while external forces are forces that act on the system from outside sources.

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