Net Force on a circular current carrying wire, from an infinite wire.

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SUMMARY

The discussion focuses on calculating the net magnetic force on a circular current-carrying wire due to an infinite straight wire. The magnetic field Bp at point P is derived from the current I1, and the Lorentz force dF is expressed in terms of its components. The net force Fnet is ultimately derived as Fnet = µoI1I2(1 - d/√(d² - a²))ŷ. Participants noted challenges in integrating to find Fnet, with some resorting to Mathematica for assistance.

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bluecadetthree
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Homework Statement



-I've attached a picture of the problem-

An infinitely long straight wire of steady current I1 is placed to the left of a circular wire of current I2 and radius a as shown. The center of the circular wire is distance d(≥ a) away from the straight wire. Let’s find the net magnetic (Lorentz) force acting on the entire circular wire as follows:

(A) Express the magnetic field Bp at point P (due to the
current I1) in given quantities (including its direction).

(B) The Lorentz force due to the magnetic field Bp acting on a small current segment I2dℓ at P is given by

dF = I2dℓ × Bp

Express dF = (dFx, dFy, dFz) in component representation in given quantities.

(C) By integrating your results from (B) show explicitly that the net Lorentz force for the
entire circular wire is given by

Fnet = µoI1I2\left(1-\frac{d}{\sqrt{d<sup>2</sup>-a<sup>2</sup>}}\right)\hat{<b>y</b>}​
<br /> <br /> <br /> <h2>Homework Equations</h2><br /> <br /> Most given in question.<br /> <br /> <div style="text-align: center"><b>B</b><sub>p</sub>=\frac{-μ<sub>0</sub>I<sub>1</sub>}{2π(d+x)}​</div><br /> <br /> <h2>The Attempt at a Solution</h2><br /> <br /> The first two parts I got through pretty easily. Part (A) was just giving the equation of the B-field for an infinite wire. For part (B) I ended up with:<br /> <br /> <div style="text-align: center">d<b>F</b>=\left(\frac{-μ<sub>0</sub>I<sub>1</sub>I<sub>2</sub>acosødø}{2(d+acosø)}\right)\hat{x}+\left(\frac{-μ<sub>0</sub>I<sub>1</sub>I<sub>2</sub>asinødø}{2(d+acosø)}\right)\hat{y}​</div><br /> which I got from taking the cross product of I<sub>2</sub>dl and <b>B</b><sub>p</sub>, and am fairly certain is correct.<br /> <br /> Now, for part (C) I keep getting stuck, I see what I'm supposed to get for <b>F</b><sub>net</sub>, but my answer always has a natural log, or becomes zero, and I don't know how else to approach the problem.
 

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Hello bluecadeetthree. Welcome to PF!

bluecadetthree said:
For part (B) I ended up with:

dF=\left(\frac{-μ_0I_1I_2a\cos\phi d\phi}{2(d+a\cos\phi)}\right)\hat{x}+\left(\frac{-μ_0I_1I_2a\sin\phi d\phi}{2(d+a\cos\phi)}\right)\hat{y}​

which I got from taking the cross product of I2dl and Bp, and am fairly certain is correct.

Yes, I think that's correct. (I tried to fix the latex, hope I got it the way you intended.)

Now, for part (C) I keep getting stuck, I see what I'm supposed to get for Fnet, but my answer always has a natural log, or becomes zero, and I don't know how else to approach the problem.

The integration of the y-component is straightforward. (The answer for this component should also be evident by symmetry.) The x-integration seems more difficult. I threw it into Mathematica and it popped out the answer. I also managed to do it by converting it to a contour integral in the complex plane. I'm not seeing an elementary way to do it, but I'm probably just not seeing it. I spent a few minutes searching integral tables on the internet but did not find it.

The answer for the net force that you stated in part (C) appears to have the wrong direction.
 
I was thinking the given net force had the wrong direction. I'll have to email my professor about that. Thanks for your help!
 

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