Net forces on a charge particle

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Homework Help Overview

The discussion revolves around the net forces acting on charged particles, specifically in the context of a physics test question. The original poster presents calculations regarding the forces on a positive charge due to other charges and seeks validation of their approach and conclusions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the net force on a charge and questions the correctness of their calculations and reasoning. Other participants suggest checking the validity of multiple answers and emphasize the importance of understanding the problem rather than seeking reassurance.

Discussion Status

Participants are exploring different interpretations of the problem, with some offering tips on how to approach similar questions. The original poster expresses concern about a discrepancy between their conclusion and the marking key, indicating a productive discussion about the problem's context.

Contextual Notes

The original poster notes that the question was part of a physics test and mentions the marking key indicated a different answer than their own calculations. This context raises questions about the clarity and quality of the question itself.

pondzo
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Homework Statement



I have attatched a snapshot explaining the question

Homework Equations



## \vec{F} = \frac{kq_{1}q_{2}}{r^2}\hat{r} ##

The Attempt at a Solution



First I will calculate the force on the left charge due to the other two

## \vec{F}_{net} = \frac{-kq^2}{d^2}(-1,0)+\frac{kq^2}{(2d)^2}(-1,0) = (\frac{3kq^2}{4d^2},0) ##
Which means the left positive charge will feel a force pulling it inwards, and through symmetry I can say that the right positive charge will be pulled inwards due to the force of the other charges.
Also for the negative charge; ## \vec{F}_{net} = \frac{-kq^2}{d^2}(-1,0)+\frac{-kq^2}{d^2}(1,0) = 0 ##
Based on this i would choose option D.

I was wondering if I have come to the right conclusion, if my calculations are correct, and if the way I approach the problem is correct. Thank you.
 

Attachments

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You need reassurance ? PF isn't really meant for that.
Or do you want some tips for this kind of (low didactical quality) questions ?

First you have to check if only one answer is right, or that perhaps more than one (or, wow, none) is correct.
Here it clearly says ONE, so no problemo.

Second: try to be economical: if no calculations are needed, don't make them. Same charge further away = less F suffices. Or: twice as far, quarter the force.

Then: A and B are clearly nonsense. So is C (no calculating needed).
Elementary, Watson: D is left and it passes scrutiny.
Double check and move on to the next exercise.

[edit] and yes, your calculations are correct...
 
Well actually, this was a question on my physics test. And yes it was the easiest low quality question, which is why I posted it in the "introductory physics" section, just in case you missed that.

Anyway the point is, in the marking key, the solution was listed as E. So I wanted to see what the PF community thought before I made an appeal. But thanks for your comments anyway.
 
Ah, you saved a nice bombshell for later.

I'll add a tip: read all answers before embarking on choosing something. More or less as a reminder to myself (I missed E completeley :redface:, a reason to be modest instead of feeling insulted...).

Make your appeal ! And don't mention PF, it really isn't meant for that -- but please tell us how it went !
 
BvU said:
You need reassurance ? PF isn't really meant for that.
My understanding of the rules is that this kind of question is perfectly acceptable.
 

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