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1. Homework Statement
I have attatched a snapshot explaining the question
2. Homework Equations
## \vec{F} = \frac{kq_{1}q_{2}}{r^2}\hat{r} ##
3. The Attempt at a Solution
First I will calculate the force on the left charge due to the other two
## \vec{F}_{net} = \frac{kq^2}{d^2}(1,0)+\frac{kq^2}{(2d)^2}(1,0) = (\frac{3kq^2}{4d^2},0) ##
Which means the left positive charge will feel a force pulling it inwards, and through symmetry I can say that the right positive charge will be pulled inwards due to the force of the other charges.
Also for the negative charge; ## \vec{F}_{net} = \frac{kq^2}{d^2}(1,0)+\frac{kq^2}{d^2}(1,0) = 0 ##
Based on this i would choose option D.
I was wondering if I have come to the right conclusion, if my calculations are correct, and if the way I approach the problem is correct. Thank you.
I have attatched a snapshot explaining the question
2. Homework Equations
## \vec{F} = \frac{kq_{1}q_{2}}{r^2}\hat{r} ##
3. The Attempt at a Solution
First I will calculate the force on the left charge due to the other two
## \vec{F}_{net} = \frac{kq^2}{d^2}(1,0)+\frac{kq^2}{(2d)^2}(1,0) = (\frac{3kq^2}{4d^2},0) ##
Which means the left positive charge will feel a force pulling it inwards, and through symmetry I can say that the right positive charge will be pulled inwards due to the force of the other charges.
Also for the negative charge; ## \vec{F}_{net} = \frac{kq^2}{d^2}(1,0)+\frac{kq^2}{d^2}(1,0) = 0 ##
Based on this i would choose option D.
I was wondering if I have come to the right conclusion, if my calculations are correct, and if the way I approach the problem is correct. Thank you.
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