Net Magnetic Field at the Center of a Loop and X Distance Away From a Wire

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SUMMARY

The discussion focuses on calculating the radius of a magnetic loop given the relationship between two currents, I2 = 6.61I1, and the condition that the net magnetic field at the center of the loop is zero. The relevant equations for magnetic fields are provided: B for a straight wire is defined as B = (μ0*I)/(2π*r), and for a loop as B = (μ0*I)/(2*r). The user attempts to relate the magnetic fields from both configurations but encounters difficulties in solving for the radius.

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  • Understanding of magnetic fields generated by currents
  • Familiarity with the Biot-Savart Law
  • Knowledge of the right-hand rule for determining magnetic field direction
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BornSurvivor
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Homework Statement


https://fbcdn-sphotos-a.akamaihd.net/hphotos-ak-prn1/553004_1959186995753_1725123128_934768_456680196_n.jpg
In case the words are too small:
I2= 6.61I1
The net magnetic field at center of loop is 0.
I'm looking for the radius of the loop

Homework Equations


for straight wire: B=(u0*I)/(2[itex]\pi[/itex]*r)
for loop: B= (u0*I)/(2*r)

The Attempt at a Solution


So, since the two magnetic fields are perpendicular to each other: √(B12+B22)=0
I tried to find H in terms of R by using the right hand rule. I2/I1=(B2*H*[itex]\pi[/itex])/(B1*R) so H= -(6.61R/[itex]\pi[/itex])
But now I'm stuck, and I don't know if my work so far is even right.
 
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Hi BornSurvivor! :smile:

(pleeeeeease don't post such wide images! :redface:)
BornSurvivor said:
So, since the two magnetic fields are perpendicular to each other …

No, a loop current's magnetic field goes along the axis of the loop,

and a straight line current's magnetic field goes in loops around the line. :wink:
 

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