In case the words are too small:
The net magnetic field at center of loop is 0.
I'm looking for the radius of the loop
for straight wire: B=(u0*I)/(2[itex]\pi[/itex]*r)
for loop: B= (u0*I)/(2*r)
The Attempt at a Solution
So, since the two magnetic fields are perpendicular to each other: √(B12+B22)=0
I tried to find H in terms of R by using the right hand rule. I2/I1=(B2*H*[itex]\pi[/itex])/(B1*R) so H= -(6.61R/[itex]\pi[/itex])
But now I'm stuck, and I don't know if my work so far is even right.
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