Neutron colliding with an atom

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SUMMARY

The discussion centers on calculating the minimum kinetic energy required for a neutron to cause an inelastic collision with a hydrogen atom at rest. The mass of both the neutron and hydrogen atom is specified as 1.67 x 10-27 kg. Participants utilized conservation of momentum and energy equations, specifically v = v1 + v2 and v2 = v12 + v22 + 2E/m, where E represents the energy released due to electronic transition. The key insight involves maximizing energy availability for excitation by minimizing the difference between final velocities.

PREREQUISITES
  • Understanding of conservation of momentum and energy principles
  • Familiarity with inelastic collisions in physics
  • Basic knowledge of atomic structure and electronic transitions
  • Ability to manipulate algebraic equations and derivatives
NEXT STEPS
  • Study inelastic collision dynamics in particle physics
  • Learn about energy levels and electronic transitions in hydrogen
  • Explore the application of derivatives in physics problems
  • Investigate neutron interactions with various atomic structures
USEFUL FOR

Students studying physics, particularly those focusing on particle interactions, atomic physics, and collision theory. This discussion is beneficial for anyone looking to deepen their understanding of inelastic collisions and energy transfer in atomic systems.

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Homework Statement


A neutron moving with a speed v makes a head-on collision with a hydrogen atom in ground state kept at rest. Find the minimum kinetic energy of the neutron, for which inelastic collision may take place. Mass of neutron = Mass of Hydrogen = 1.67 x 10-27kg

The Attempt at a Solution



Let the final velocities of the nuetron and hydrogen atom be v1 and v2.
I used conservation of momentum and energy to get the following equations-
v = v1 + v2
v2 = v12 + v22 + 2E/m

where E is the energy released due to electronic transition.
How do I find out the min. kinetic energy?
 
Last edited:
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Abdul Quadeer said:
Let the final velocities of the nuetron and hydrogen atom be v1 and v2.
I used conservation of momentum and energy to get the following equations-
v = v1 + v2
v2 = v12 + v22 + 2E/m

where E is the energy released due to electronic transition.
How do I find out the min. kinetic energy?

If you square your first equation and compare the result to the second equation, you may spot an interesting relationship between the E and the product of the velocities.

Then consider that for maximum energy availability for the excitation you want the difference between the final velocities to head towards zero.
 
Beautiful!
I was thinking all time about using derivatives.
Thank You.

Btw we have to consider the minimum energy availability for the excitation :smile:
 
Last edited:

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