- #1
Koh Eng Kiat
- 10
- 0
Homework Statement
The plates of a parallel plate capacitor of capacitance C0 are
horizontal. Into the gap a slab of dielectric material with K=2 is placed,
filling the bottom half of the gap between the plates. What is the
resulting new capacitance?
Homework Equations
C = Q/V = κɛ0A/d
The Attempt at a Solution
Co = ɛ0A/d
Cf = kɛ0A/d = ((ɛ0)(0.5A)/d) + ((2ɛ0)(1/2a)/(d)) = (ɛ0A/2d) +(ɛ0A/d) = (ɛ0A/d) + (2ɛ0A/2d) = (3ɛ0A/2d)
Cf = 3/2 Co
The correct answer is 4/3 Co. Guys, can anyone help me out? I have no idea how to derive the correct answer.