- #1

Koh Eng Kiat

- 10

- 0

## Homework Statement

The plates of a parallel plate capacitor of capacitance C0 are

horizontal. Into the gap a slab of dielectric material with K=2 is placed,

filling the bottom half of the gap between the plates. What is the

resulting new capacitance?

## Homework Equations

C = Q/V = κɛ0A/d

## The Attempt at a Solution

Co = ɛ0A/d

Cf = kɛ0A/d = ((ɛ0)(0.5A)/d) + ((2ɛ0)(1/2a)/(d)) = (ɛ0A/2d) +(ɛ0A/d) = (ɛ0A/d) + (2ɛ0A/2d) = (3ɛ0A/2d)

Cf = 3/2 Co

The correct answer is 4/3 Co. Guys, can anyone help me out? I have no idea how to derive the correct answer.