- #1

bengt2665

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**The weight of the cart is 4 N. The weight of the hanging mass is 4 N.**

Friction of the cart on the track is a constant force of 2 N magnitude.

The mass of the string, the mass of the pulley, and the friction of the pulley can be neglected.

What is the magnitude of the acceleration of the cart if g is the free-fall acceleration?

Picture attached.

Friction of the cart on the track is a constant force of 2 N magnitude.

The mass of the string, the mass of the pulley, and the friction of the pulley can be neglected.

What is the magnitude of the acceleration of the cart if g is the free-fall acceleration?

Picture attached.

The answer is to be given in terms of g.

Okay, here's what I have so far:

By drawing a free body diagram I manage to get these two equations for the forces acting on both the cart and the hanging mass:

I'm assuming positive acceleration to the right of the cart and down for the mass.

For the cart: T - Ff = ma

For the mass: T - mg = ma

(since they have the same weight, there is only one m)

We know that the weight of these two is 4N each so for both, 4 = ma (i'm predicting this might not be right...)

I'm having trouble applying their given information (4N weight for both masses) with the equations I'm coming up with, for example I don't know what this 4N corresponds to...

Is it 4N = m.a for the cart and 4N = mg for the hanging mass?

How do I apply the information they are giving me?

Thanks!