- #36
Saitama
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ehild said:How is the acceleration of M related to the vertical acceleration of 2M and the acceleration of 5M in the inertial frame of reference? The length of the string can not change. And M moves with respect to 5M.
Start a new page, denote the horizontal acceleration components by a1,a2,a5, the vertical acceleration of 2M by a2y.
Decide a positive x and positive y direction and write up all equations for a1, a2, a5, and a2y.
ehild
The direction to the right is positive x-axis and vertically upwards is y-axis.
Equation for motion of M: ##T=Ma_1##
Equation for motion of 2M:
In horizontal direction: ##N=2Ma_2##
In vertical direction: ##2Mg-T=2Ma_{2y}##
Equation for motion of 5M: ##T-N=5Ma_5##
I only have ##a_2=a_5## but I still need one more equation to relate ##a_1## and ##a_{2y}##. I still can't figure out what I am missing. :(