Newtonian Gravity: Describing as Vector Field

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SUMMARY

This discussion provides a detailed mathematical description of Newtonian gravity as a vector field. It begins with a mass located at \(\vec{x}_{0}=(x_{0},y_{0},z_{0})\) with mass \(m_{0}\), generating a force per unit mass at any point \(\vec{x}\neq\vec{x}_{0}\) given by \(\vec{f}(x,y,z)=-\frac{Gm_{0}}{||\vec{x}-\vec{x}_{0}||^{3}}(\vec{x}-\vec{x}_{0})\). The resultant force \(\vec{F}\) acting on an object of mass \(M\) at \((x,y,z)\) is derived by multiplying \(\vec{f}\) with \(M\). Additionally, the discussion presents an alternative representation using spherical coordinates, expressed as \(\vec F (r, \theta, \phi) = - \frac{G m_0}{r^2} \hat r\), where \(\hat r\) indicates the unit vector in the radial direction.

PREREQUISITES
  • Understanding of vector fields in physics
  • Familiarity with Newton's law of universal gravitation
  • Knowledge of spherical coordinates
  • Basic grasp of mathematical notation and operations
NEXT STEPS
  • Study the derivation of gravitational force in vector form
  • Explore the implications of gravitational fields in different coordinate systems
  • Learn about the concept of gravitational potential energy
  • Investigate the applications of vector fields in other areas of physics, such as electromagnetism
USEFUL FOR

Students of physics, educators teaching classical mechanics, and researchers interested in gravitational theories will benefit from this discussion.

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how would you describe Newtonian gravity as a vector field?
 
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Well, as a simple case, suppose you've got a mass positioned at location [tex]\vec{x}_{0}=(x_{0},y_{0},z_{0})[/tex] with mass [itex]m_{0}[/itex]

Then, for any spatial point [tex](x,y,z)=\vec{x}\neq\vec{x}_{0}[/tex]
that mass generates at that point a force per unit mass:
[tex]\vec{f}(x,y,z)=-\frac{Gm_{0}}{||\vec{x}-\vec{x}_{0}||^{3}}(\vec{x}-\vec{x}_{0})[/tex]

The force [itex]\vec{F}[/itex] acting upon an object of mass M situated at (x,y,z) is then found by multiplying f with M.
 
Another form you sometimes see assumes that the mass is at the origin, and uses spherical coordinates:

[tex]\vec F (r, \theta, \phi) = - \frac{G m_0}{r^2} \hat r[/tex]

where [itex]\hat r[/itex] is the unit vector in the outward radial direction at that particular point.
 

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