"Two boxes, m1=1.0 kg witha coefficient of kinetic friction of 0.10 amd m2=2.0 kg with a coefficient of 0.20, are placed on a plane inclined at 30 degrees. (a) What acceleration does each box experience? (b) If a taut string is connecting the boxes with m2 farther down the slope, what is the acceleration of each box?"(adsbygoogle = window.adsbygoogle || []).push({});

So, I have part (a) (I believe!):

x direction: m1: m1gsin30 -Ffr=m1a1 (same for m2, but sub m2 for m1)

y direction: Fn = m1gsin30

For m1, migsin30=(muk)Fn = m1a1, you place in the appropriate values from the question and solve for a1= 4.1 m/s2

You go through the similar steps for m2 and solve for a2= 3.2 m/s2

But I'm a little confused on how exactly to explain part (b):

I think that the accelerations would be the same, but we were taught that whenever boxes are connected by a taut string, the acceleration for the boxes is the same, and it is treated as a system. But, since m1 is in back and has a faster acceleration, wouldn't it go faster so that the cord is no longer taut and the boxes are essentially not connected? Or am I thinking about it wrong and it should be treated as a system?

thanks in advance!

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Newtonian mechanics, incline, acceleration FUN

**Physics Forums | Science Articles, Homework Help, Discussion**