Newtons 2nd Law corrected for Relativity

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SUMMARY

The discussion focuses on correcting Newton's Second Law for relativity in the context of a damped harmonic oscillator. The modified equation is presented as d(mvγ)/dt = -kx - cv, where γ = 1/√(1-v²/c²). It is established that only the mass (m) needs to be corrected as a function of velocity, without requiring adjustments for length contraction or time dilation in the coordinates. Additionally, the complexities of the force between two moving charges are highlighted, necessitating the application of special relativity and retarded fields for accurate calculations.

PREREQUISITES
  • Understanding of Newton's Second Law (F = d(mv)/dt)
  • Familiarity with the concepts of special relativity (γ = 1/√(1-v²/c²))
  • Knowledge of damped harmonic oscillators and their equations (F = -kx - cv)
  • Basic principles of electromagnetism, particularly Coulomb's Law (F = kpe/r²)
NEXT STEPS
  • Study the application of special relativity in classical mechanics, focusing on mass as a function of velocity.
  • Explore advanced electromagnetic theory, particularly the treatment of forces between moving charges.
  • Investigate the concept of retarded fields in electromagnetism for accelerating charges.
  • Review the mathematical derivation of the equations governing damped harmonic oscillators under relativistic conditions.
USEFUL FOR

This discussion is beneficial for physicists, students of advanced mechanics, and anyone interested in the intersection of classical mechanics and relativity, particularly in the context of oscillatory systems and electromagnetic interactions.

SSGD
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F = d(mv)/dt Newtons 2nd Law
F = -kx Spring Force
F = -cv Damping Force

d(mv)/dt = -kx + -cv

How would you correct the equation for a damped harmonic oscillator for relativity. If it is possible. I just want a one dimensional solution unless you have to go to a two dimensional or three dimensional model to because of relativity.
 
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d(mv\gamma)/dt = -kx + -cv, with \gamma=1/\sqrt{1-v^2/c^2}.
 
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That is it? You wouldn't have to correct x for length contraction or t for time dilation. Just correct the m as a function of velocity.
 
SSGD said:
That is it? You wouldn't have to correct x for length contraction or t for time dilation. Just correct the m as a function of velocity.

That's right. They're your x and t coordinates, and you aren't moving relative to yourself.
 
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Oh... I understand. You have been a lot of help.
 
From some of the reading I have done, magnetism is product of relativity and electric fields.

Columbic Force between a positive charge and a negative charge is

F = kpe/r2 so because I am using my own position and time then check me if I have it.

d(mvγ)=kpe/r2 or is there more to it because the two particle are moving relative to each other as well.
 
There is much more to it. The equation for the force between two moving charges needs special relativity if they have constant velocity, and 'retarded fields' if they are accelerating. This is covered in advanced EM texts.
 

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