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Newton's Law of Cooling. little question about 'Specific heat' of Mercury

  1. Apr 15, 2009 #1
    Newton's Law of Cooling

    Time Required to Cool (or heat) an Object [Also known as Newton's Law of Cooling]

    t=mCp(Ts-Tf)/Q

    Where;

    Q is the heat added (or being removed) from the object in watts
    m is the mass (weight) of the object in Kg
    Cp is the Specific heat of the object material in J/Kg C
    t is the time required to cool down (or heat up) the object in seconds
    Ts is the starting temperature in C
    Tf is the final temperature in C

    Here is what i am entering:

    Q - 1700 W
    m - 500 KG
    Cp - ??????
    Ts - 1 degC
    Tf - 67 degC

    But what should i enter for the 'Specific heat of the object material in J/Kg C'?
    The Object is Mercury.

    Thank you
     
  2. jcsd
  3. Apr 15, 2009 #2
    Cp=0.139 joules per gram per degree C.
     
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