Newton's law of gravitational attraction help?

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Homework Help Overview

The discussion revolves around a problem involving Newton's law of gravitational attraction, specifically calculating the position of a third mass that experiences no net gravitational force from two other spherical masses located on the x-axis.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the distances from the third mass to the other two masses, questioning how to express these distances in terms of the variable x. There is an exploration of the ratio of distances and how to set up the equations based on gravitational force principles.

Discussion Status

Participants are actively engaging with the problem, clarifying the definitions of the distances involved and substituting expressions into the gravitational force ratio. There is a collaborative effort to derive the necessary relationships without reaching a final solution yet.

Contextual Notes

There is an implicit assumption that the third mass must be positioned between the two given masses, and the total distance between the two masses is fixed at 61.2 m. Participants are navigating the constraints of the problem while ensuring the gravitational forces balance out.

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[SOLVED] Newton's law of gravitational attraction help?

Homework Statement


M1 is a spherical mass (38.6 kg) at the origin. M2 is also a spherical mass (10.3 kg) and is located on the x-axis at x = 61.2 m. At what value of x would a third mass with a 15.0 kg mass experience no net gravitational force due to M1 and M2?


Homework Equations


F=(Gm1m2)/R^2


The Attempt at a Solution


The force of m1 on m3 and m2 on m3 should be equal, so
Gm1m3/r1^2 := Gm2m3/r2^2

G and m3 are constant, so rearrange and get

sqrt (m1/m2) = r1/r2

not sure what to do here, should i just multiply this ratio by the distance 61.2m?
 
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But what are [tex]r_1[/tex] and [tex]r_2[/tex] in terms of x?
 
r1 + r2 = x
 
If r1 is the distance from mass 1 to mass 3, and r2 is the distance from mass 3 to mass 2, and the distance between mass 1 and mass 2 is 61.2, then what is r2 (the distance between mass 3 and mass 2)?
 
r2 = 61.2 - r1

ok, so substitute this into the ratio r1/r2 --> r1/(61.2-r1) = sqrt (m1/m2)

?
 
Yes, and then solve for r_1.
 

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