Hi I have a problem I need someone to check over and see if I have it right!(adsbygoogle = window.adsbygoogle || []).push({});

Thank you for trying in advance

Responding to an alarm, a 92kg fireman slides down a pole to the ground floor, 3.2m below. The fireman starts at rest and lands with a speed of 4.9 m/s. Find the average force exerted on the fireman by the pole.

m=92 Kg, d=3.2m, Vf= 4m/s

I found time first: (Can I do that?)

y-vector

y=0.5 (Voy+Vy)t

3.2m =0.5 (0+4m/s)t

t=1.6s

y=yo+Voyt+0.5ayt^2

ay=2(y-yo) / t^2

ay = (2)(0-3.2m) / 1.6s

ay=-4m/s^2

Sum of Fy= F-mg

F-mg=ma

F= may+mg = m(ay+g)

F = (92kg)(-4m/s^2+9.81m/s^2)

F= 534.5N

Thanks

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