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Newtons Laws, Finding tension in the tow cable and foce

  • Thread starter mjm3
  • Start date
  • #1
5
0

Homework Statement


Just started tension problems and having some trouble figuring out how to approach the problem. Thanks for any help in advance.

Consider a rocket that is taking off and towing a large container of trash. The
rocket’s engines exert a force, F, that causes the rocket and container to accelerate at
4.50 m/s2. The rocket has a mass of 3.00 × 103 kg, and the container has a mass of
1.00 × 103 kg. Find the tension in the tow cable and the force, F.


Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
662
307
Start with free body diagram and show us what you get.
 
  • #3
5
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mass a of the rocket. FN upward is the F(RA), downward we have m(ag) and also m(bg)?
mass b of container. Upward would be F(t) and FN would be F(RB)? downward m(bg).

I have the most trouble the free body diagrams.

Work. Part 1, A= F / ma+mb. F=A(ma+mb) = 1.80x10^4 N
Part 2, Ft=mb * a = 4.50x10^3 N
 
  • #4
662
307
Upward would be F(t) and FN would be F(RB)? downward m(bg).
What is FN? :confused:
Work. Part 1, A= F / ma+mb. F=A(ma+mb) = 1.80x10^4 N
Part 2, Ft=mb * a = 4.50x10^3 N
Seems good. :smile:
 
  • #5
5
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Sorry I was meaning to write it as the Normal Force, NF better?
 
  • #6
662
307
Sorry I was meaning to write it as the Normal Force, NF better?
I was afraid so...there is no normal force here! Normal forces come in play when there is a body in contact with another. See: http://en.wikipedia.org/wiki/Normal_force
For normal force it is general practice to write Fn or just N.
 
  • #7
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Thanks for the help. Just clarifying Fn made this system much easier to understand.
 

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