Newtons Laws, Finding tension in the tow cable and foce

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Homework Help Overview

The discussion revolves around a physics problem involving Newton's laws, specifically focusing on calculating the tension in a tow cable and the force exerted by a rocket towing a container. The scenario describes a rocket accelerating while towing a container of trash, with given masses and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of free body diagrams to analyze the forces acting on both the rocket and the container. There are attempts to clarify the roles of different forces, including tension and normal force, with some confusion about the normal force's relevance in this context.

Discussion Status

The discussion is active, with participants providing insights and clarifications regarding the free body diagrams and the forces involved. Some guidance has been offered regarding the terminology of forces, particularly the normal force, which has helped clarify the problem for some participants.

Contextual Notes

There is a noted confusion regarding the normal force in the context of this problem, as it may not be applicable given the scenario described. Participants are working through the implications of this in their analysis.

mjm3
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Homework Statement


Just started tension problems and having some trouble figuring out how to approach the problem. Thanks for any help in advance.

Consider a rocket that is taking off and towing a large container of trash. The
rocket’s engines exert a force, F, that causes the rocket and container to accelerate at
4.50 m/s2. The rocket has a mass of 3.00 × 103 kg, and the container has a mass of
1.00 × 103 kg. Find the tension in the tow cable and the force, F.


Homework Equations





The Attempt at a Solution

 
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Start with free body diagram and show us what you get.
 
mass a of the rocket. FN upward is the F(RA), downward we have m(ag) and also m(bg)?
mass b of container. Upward would be F(t) and FN would be F(RB)? downward m(bg).

I have the most trouble the free body diagrams.

Work. Part 1, A= F / ma+mb. F=A(ma+mb) = 1.80x10^4 N
Part 2, Ft=mb * a = 4.50x10^3 N
 
mjm3 said:
Upward would be F(t) and FN would be F(RB)? downward m(bg).

What is FN? :confused:
mjm3 said:
Work. Part 1, A= F / ma+mb. F=A(ma+mb) = 1.80x10^4 N
Part 2, Ft=mb * a = 4.50x10^3 N
Seems good. :smile:
 
Sorry I was meaning to write it as the Normal Force, NF better?
 
mjm3 said:
Sorry I was meaning to write it as the Normal Force, NF better?
I was afraid so...there is no normal force here! Normal forces come in play when there is a body in contact with another. See: http://en.wikipedia.org/wiki/Normal_force
For normal force it is general practice to write Fn or just N.
 
Thanks for the help. Just clarifying Fn made this system much easier to understand.
 

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