Newton's Laws/ Tension Forces Problem

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SUMMARY

This discussion focuses on calculating the tension forces in a two-object system where the top object (m1) has a mass of 18 kg and the bottom object (m2) has a mass of 12 kg. The tension in the strings is calculated using the equations of motion, specifically FNet = ma and Fg = mg, with gravitational acceleration (g) set at 9.8 m/s². The correct tension values are T1 = 176.4 N for m1 and T2 = 117.6 N for m2 when at rest. When an additional force of 45 N is applied downward on m1, the tension calculations must account for the combined mass of both objects, leading to a revised tension of T1 = 203.4 N, which was initially miscalculated.

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BEANTOWN
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Homework Statement



Two Objects are hung from strings. The top object (m1) has a mass of 18 kg and the bottopm object (m2) has a mass of 12 kg.

Looks like this:
http://www.google.ca/imgres?q=physi...w=158&start=0&ndsp=15&ved=1t:429,r:6,s:0,i:77

(a). Calculate tension in each string.

(b) Calculate the tension in each string if you pull down on m1 with a force of 45 N [down]

Homework Equations



FNet = ma
Fg = mg
g = 9.8

The Attempt at a Solution


I knew how to do (a).
I creted a free body diagram for each weight first.
Then for m1:
FNet = T1 - Fg
0 = T1 - Fg ----> FNet = 0 because it is at rest
T1 = Fg
T1 = (18)(9.8)
T1= 176.4 N
And then i did the same for the second one, and came up with T2 = 117.6

Then I got to (b). But I am lost.
I attemted to find acceleration by doing:
FNet = Fa ----> Fa = the 45 N
FNet = 45 N
ma = 45 N
(m1 + m2)a= 45 ---- a= 45/(18 + 12)
a = 1.5
So:
FNet = T1 - Fg1
(18)(1.5) + (9.8)(18) = T1
T1 = 203.4 N
According to my answer key, this is not right. Please help.
 
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BEANTOWN said:

Homework Statement



Two Objects are hung from strings. The top object (m1) has a mass of 18 kg and the bottopm object (m2) has a mass of 12 kg.

Looks like this:
http://www.google.ca/imgres?q=physi...w=158&start=0&ndsp=15&ved=1t:429,r:6,s:0,i:77

(a). Calculate tension in each string.

(b) Calculate the tension in each string if you pull down on m1 with a force of 45 N [down]

Homework Equations



FNet = ma
Fg = mg
g = 9.8

The Attempt at a Solution


I knew how to do (a).
I creted a free body diagram for each weight first.
Then for m1:
FNet = T1 - Fg
0 = T1 - Fg ----> FNet = 0 because it is at rest
T1 = Fg
T1 = (18)(9.8)
T1= 176.4 N
And then i did the same for the second one, and came up with T2 = 117.6

Then I got to (b). But I am lost.
I attemted to find acceleration by doing:
FNet = Fa ----> Fa = the 45 N
FNet = 45 N
ma = 45 N
(m1 + m2)a= 45 ---- a= 45/(18 + 12)
a = 1.5
So:
FNet = T1 - Fg1
(18)(1.5) + (9.8)(18) = T1
T1 = 203.4 N
According to my answer key, this is not right. Please help.

Red line above.

T1 is supporting BOTH masses so the mass used to calculate T1 should be 30kg.

T2 is supporting only M2 so your answer is probably correct.

With a free body diagram:-

for M2:

M2g down, T2 up so your answer should be correct

for M1:

M1g down + T2 down, T1 up

For part b, there is no acceleration; merely an EXTRA 45N down in the free body diagram for M1
 

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