Newton's second law to find mass

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Homework Help Overview

The problem involves a helicopter propelling air downwards and determining the mass of the helicopter based on the forces involved, specifically using Newton's second law. The context includes the acceleration of the helicopter and the mass flow rate of air.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the relationship between force, mass, and acceleration. There are attempts to clarify the forces acting on the helicopter and how they relate to hovering versus rising.

Discussion Status

Some participants have provided guidance on analyzing the forces acting on the helicopter, suggesting the use of a free body diagram. There is acknowledgment of a misunderstanding regarding the forces required for hovering and the implications of acceleration.

Contextual Notes

Participants are exploring the implications of the helicopter's acceleration and the mass of air being propelled, questioning the assumptions made in the original calculations. There is a reference to a manual answer that differs from the calculations presented.

songoku
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Homework Statement


the rotor blades of a helicopter propel 2500 kg of air vertically downwards every second. The air, initially at rest, is accelerated to a speed of 15 ms-1. If the helicopter starts to rise with an acceleration of 12.5 ms-2, the mass of the helicopter is...

a. 1680 kg
b. 2500 kg
c. 2000 kg
d. 3000 kg
e. 3750 kg


Homework Equations


F = dp/dt


The Attempt at a Solution


let m1 = mass of helicopter and m2 = mass of air
When the helicopter reaches 15 ms-1 :

F = dp / dt

m1g = d(m2v) / dt

m1g = v dm2/dt

m1 = 15 * 2500 / 10 = 3750 kg

But in the manual, the answer is (a). Where is my mistake? Thanks
 
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songoku said:

Homework Statement


the rotor blades of a helicopter propel 2500 kg of air vertically downwards every second. The air, initially at rest, is accelerated to a speed of 15 ms-1. If the helicopter starts to rise with an acceleration of 12.5 ms-2, the mass of the helicopter is...

a. 1680 kg
b. 2500 kg
c. 2000 kg
d. 3000 kg
e. 3750 kg


Homework Equations


F = dp/dt


The Attempt at a Solution


let m1 = mass of helicopter and m2 = mass of air
When the helicopter reaches 15 ms-1 :

F = dp / dt

m1g = d(m2v) / dt

m1g = v dm2/dt

m1 = 15 * 2500 / 10 = 3750 kg

But in the manual, the answer is (a). Where is my mistake? Thanks
What if the helicopter simply hovered? What downward force would that require? Now add to that the upward acceleration. How much force does that require? Add them together.

AM
 
Hi AM

I don't really get what you mean...If the helicopter simply hovers, then the force required will the same as its weight, which like what I've done above. And there will be no acceleration if the helicopter hovers.

Thanks
 
songoku said:
Hi AM

I don't really get what you mean...If the helicopter simply hovers, then the force required will the same as its weight, which like what I've done above. And there will be no acceleration if the helicopter hovers.

Thanks
Do a free body diagram. The net force = mass x acceleration. What are the forces that act on the helicopter? Add them vectorally and set that net force to equal the mass x acceleration.

AM
 
Hi AM

Oh now I understand where my mistake was. Thanks a lot for your help ! :smile:
 

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