Newton's third law -- Calculate the recoil of a paintball gun

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SUMMARY

The discussion revolves around calculating the recoil of a paintball gun using Newton's laws of motion. A paintball with a mass of 0.15 kg is fired at a velocity of 45 m/s, and the paintball gun has a mass of 5.5 kg. The acceleration of the paintball is calculated to be 450 m/s², leading to a net force of 68 N on the paintball. Consequently, the recoil acceleration of the paintball gun is determined to be 12 m/s².

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Baran
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Homework Statement
A paintball with a mass of 0.15 kg is fired from a paintball gun that has a mass of 5.5 kg. The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s. Calculate the acceleration of the paintball gun.
Relevant Equations
Givens:
Mass of paintball = 0.15 kg
Mass of paintball gun = 5.5 kg
initial velocity of paintball = 45 m/s [N]
time = 0.10 s
I've been stuck on this for sometime now, and am unsure how to approach this question.
 
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Baran said:
Homework Statement:: A paintball with a mass of 0.15 kg is fired from a paintball gun that has a mass of 5.5 kg. The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s. Calculate the acceleration of the paintball gun.
Relevant Equations:: Givens:
Mass of paintball = 0.15 kg
Mass of paintball gun = 5.5 kg
initial velocity of paintball = 45 m/s [N]
time = 0.10 s

I've been stuck on this for sometime now, and am unsure how to approach this question.
First find the force on the paintball (hint: use Newton's second law).
 
nrqed said:
First find the force on the paintball (hint: use Newton's second law).
I'm confused, in order to find the net force you would need acceleration, wouldn't you?
 
Baran said:
I'm confused, in order to find the net force you would need acceleration, wouldn't you?
Yes, and you can calculate the acceleration. You know the speed of ejection and the time it took to accelerate the paintball.
 
nrqed said:
Yes, and you can calculate the acceleration. You know the speed of ejection and the time it took to accelerate the paintball.
I think I got it:

a= vf-vi/t
a= 0 m/s- 45 m/s [N] / 0.10 s
a= -450 m/s^2 [N]
a= 450m/s

(this is the paintball)
Fnet= ma
Fnet= (0.15 kg) x(450 m/s^2 )
Fnet= 68 N

(this is the paintball gun)
Fnet= ma
a= Fnet/m
a= 68 N / 5.5 kg
a= 12 m/s^2

can you check if I did this right please?
(Sorry about the black lines I don't know how to fix that)
 
looks good!
 
nrqed said:
looks good!
Thanks for all your help!
 
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