1. The problem statement, all variables and given/known data A physics student in a hot air balloon ascends vertically at a constant speed. Consider the following four forces. that arise in this question. F1 = the weight of the hot air balloon F2 = the weight of the student F3 = the force of the student pulling on the earth F4 = the force of the hot air balloon pulling on the student Which two of these forces form an "action-reaction" pair that obeys Newton's third law? a)F1 and F2 b)F2 and F3 c)F1 and F3 d)F2 and F4 e)F3 and F4 3. The attempt at a solution I think it's d) because gravity is pulling the student downwards while the hot air balloon is exerting the same force in the opposite direction, keeping the student in the basket. Is this a correct assumption?
No, this is not the 3rd law. Look up its definition in regard to the 'action-reaction' pair. Essentially, if A exerts a force on B, then B exerts an equal but opposite force on A.
I meant your answer is incorrect because what you have described is an application of newton's first law , with 2 forces acting on the same object and summing to zero. Newton's 3rd law applies to the force pairs acting on different objects. One of the multiple choices describes the correct application of Newton 3.
because the earth is pulling on the student while is is pushing away from the earth at an equal and opposite direction?
Your answer (b) is correct, but your explanation is a little bit off. The earth is pulling downward on the student with a force equal to his weight, while the student is pulling upward on the earth with a force equal to his weight.