Newton's third law problem/kinematics (Airboat problem/no friction)

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SUMMARY

The discussion centers on calculating the displacement of an airboat using Newton's third law and kinematics, specifically under conditions of no friction. The force exerted by the fan is 150 N backwards, resulting in a forward force of 150 N on the boat. Given the mass of the boat at 220 kg, the calculated acceleration is 0.68 m/s². Using the kinematics equation D = v1∆t + 1/2 at², the boat is determined to travel 1224 meters in one minute, assuming it starts from rest.

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  • Understanding of Newton's third law of motion
  • Familiarity with basic kinematics equations
  • Knowledge of force, mass, and acceleration relationships (F=ma)
  • Ability to perform unit conversions and calculations in physics
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  • Explore the effects of friction on boat dynamics in real-world scenarios
  • Learn about advanced kinematics equations and their applications
  • Investigate the principles of thrust and drag in fluid dynamics
  • Study the implications of Newton's laws in various engineering contexts
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Students studying physics, particularly in kinematics and dynamics, as well as engineers and enthusiasts interested in the mechanics of airboats and similar vehicles.

Petronius
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Homework Statement
An airboat is a special type of boat that has a large fan mounted on the back instead of a motor that sits in the water. It is used in places where the water is shallow and weedy, so motors that stick down into the water cannot be used.

If the force of the fan pushes the air backwards with 150 N, what is the forward force of the air on the boat? If the mass of the boat is 220 kg, and you ignore friction between the boat and the water, find how far the boat will travel in the first minute.
Relevant Equations
Based on unit notes I used:
Faction= -Freaction
F=ma
D= v1∆t + 1/2 at^2
Thank you very much your time!

I first found the force of the air on the boat using the principle of Newton's third law and the fact that no friction is involved.

Faction= -Freaction
150 N backwards = -150 N backwards
150 N backwards = 150 N forward

I then sought to determine the acceleration of the boat forward so that I would have enough information to solve for how far the boat will travel in the first minute (displacement).

F =ma
150 N [forward[ = (220kg)(a [forward])
a = 150 N [forward] / 220kg
a= 0.68m/s^2 |forward|

After this I sought to determine how far the boat would travel in one minute using the kinematics equation D= v1∆t + 1/2 at^2 .
My answer seems far too high and I am a bit perplexed and also wondering if there is an easier equation I could apply

I assumed v1 would be 0 since the the equation seems to state that the boat is starting from rest.

D= v1∆t + 1/2 at^2 .
D = 0 + 1/2(0.68 m/s^2)(60sec)^2
D= (0.34)(3600)
D=1224 metes

Therefore the boat travels a total of 1224 metres in a minute.

I hope my the way I have written the equations is acceptable as they do not seem to directly copy and paste from equation editor on Microsoft word.

Again, thank you for your time and any help/guidance provided.
 
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Petronius said:
Homework Statement:: An airboat is a special type of boat that has a large fan mounted on the back instead of a motor that sits in the water. It is used in places where the water is shallow and weedy, so motors that stick down into the water cannot be used.

If the force of the fan pushes the air backwards with 150 N, what is the forward force of the air on the boat? If the mass of the boat is 220 kg, and you ignore friction between the boat and the water, find how far the boat will travel in the first minute.
Homework Equations:: Based on unit notes I used:
Faction= -Freaction
F=ma
D= v1∆t + 1/2 at^2

Thank you very much your time!

I first found the force of the air on the boat using the principle of Newton's third law and the fact that no friction is involved.

Faction= -Freaction
150 N backwards = -150 N backwards
150 N backwards = 150 N forward

I then sought to determine the acceleration of the boat forward so that I would have enough information to solve for how far the boat will travel in the first minute (displacement).

F =ma
150 N [forward[ = (220kg)(a [forward])
a = 150 N [forward] / 220kg
a= 0.68m/s^2 |forward|

After this I sought to determine how far the boat would travel in one minute using the kinematics equation D= v1∆t + 1/2 at^2 .
My answer seems far too high and I am a bit perplexed and also wondering if there is an easier equation I could apply

I assumed v1 would be 0 since the the equation seems to state that the boat is starting from rest.

D= v1∆t + 1/2 at^2 .
D = 0 + 1/2(0.68 m/s^2)(60sec)^2
D= (0.34)(3600)
D=1224 metes

Therefore the boat travels a total of 1224 metres in a minute.

I hope my the way I have written the equations is acceptable as they do not seem to directly copy and paste from equation editor on Microsoft word.

Again, thank you for your time and any help/guidance provided.

That looks right. Ignoring friction is perhaps not so realistic for a boat in the water! But that's the question setter's fault.
 
Thank you very much for your time. I suppose the lack of friction means this hypothetical airboat can reach some monstrous speeds.
 
Petronius said:
Thank you very much for your time. I suppose the lack of friction means this hypothetical airboat can reach some monstrous speeds.
Yes, exactly.
 

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