Newton's Third Law-two masses on a wedge

[jiwon]

The Attempt at a Solution

8 kg block:

T-m2g = -m2a

T-m1g sin(theta)- u m1g cos (theta) = m1a
T -m2g=-m2a

subtract equations:

-m1gsin(theta)-umigcos(theta) + m2g =
(m1+m2)a

or a = g(m2-m1sin(theta)-m2cos(theta)/(m1+m2)

substituting values:

a=g(8-10sin(30)-0.2(10)cos30)/(18)

a=0.69m/s/s

b)

vf^2=v0^2+2ad to find final velocity, knowing v0=0, a=0.69m/s/s and d=0.4m

 

[semc]

Your 1st part looks good so therefore i think the second part should be alright since its just subsituting values inside. So what's your question haha