NLM Problem: More variables than equations

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Homework Help Overview

The discussion revolves around a problem related to Newton's Laws of Motion, specifically dealing with the dynamics of two masses on an incline and the forces acting on them. The original poster attempts to derive equations of motion but encounters a situation with more variables than equations.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the free body diagrams (FBDs) drawn by the original poster, questioning their accuracy and the treatment of certain forces as pseudo forces. There are inquiries about the net horizontal force acting on the system and the horizontal acceleration of the blocks. Some participants suggest drawing separate FBDs for each block to clarify the forces involved.

Discussion Status

There is ongoing exploration of the problem, with participants providing guidance on how to approach the FBDs and questioning the assumptions made by the original poster. Some participants express uncertainty about the relationship between the variables and the forces, indicating that the discussion is still active without a clear consensus or resolution.

Contextual Notes

Participants note potential errors in the original equations and emphasize the need for accurate labeling and consideration of the system's dynamics. The original poster is encouraged to revise their approach based on feedback received.

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Homework Statement
Two blocks initially at rest are kept in contact as shown in the figure. A force F is applied on the left block. The blocks are of masses ##m_1## and ##m_2##. Find the acceleration of the blocks. All surfaces are smooth.
Relevant Equations
##Force = Mass \times Acceleration##
fbd1.png

Attempt at Solution::

##m_2## is chosen as reference frame and FBD is drawn as shown above. We get the following equations:

From ##m_1## by choosing axes along and perpendicular to acceleration of ##m_1## w.r.t ##m_2## (##a'##):

$$
m_1 a' + m_1 a \cos{\theta} + m_1 g \sin{\theta} = N_1 \sin{\theta} + F \cos{\theta}
$$
$$
N+N_1 \cos{\theta} + m_1 a \sin{\theta} = m_1 g \cos{\theta} + F \sin{\theta}
$$

From ##m_2## by choosing horizontal and vertical axes:
$$
N_2 = N \cos{\theta} + m_2 g
$$
$$
m_2 a = N \sin{\theta}
$$

Which gives us four equations, but five variables, namely ##a',a,N_1 ,N_2, N##
 
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Your FBD is incorrect. ##m_1a## and ##m_2a## are not forces. If you consider the two blocks together as your system, what is the net horizontal force acting on that system? What is its horizontal acceleration? Start from there then draw two separate FBDs for each block.
 
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Please label the coordinates on the diagram, and the associated coordinate with each equation you have written down.
 
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kuruman said:
Your FBD is incorrect. ##m_1a## and ##m_2a## are not forces. If you consider the two blocks together as your system, what is the net horizontal force acting on that system? What is its horizontal acceleration? Start from there then draw two separate FBDs for each block.
umm.. ##m_1a## and ##m_2a## are pseudo forces because accelerating frame ##m_2## (with acceleration a towards right) is my Reference frame.

Net horizontal force on the two blocks as a system is F.
Sum of mass × horizontal acceleration of two blocks is F.

But how can you comment about their individual horizontal acceleration?
 
Think about a' and N1. can both be nonzero?
 
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Why ##N_1## participating in the sum of the forces if you assume the small mass is accelerating up the incline?

There are probably a few errors here. You should do as @kuruman suggest and present accurate FBD's of each block.
 
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haruspex said:
Think about a' and N1. can both be nonzero?
I think this actually solves it. Ok trying and editing to final solution...
 
So what did you get for ##a## and ##a'## as labeled in your diagram?
 
Seeker220 said:
I think this actually solves it. Ok trying and editing to final solution...
Please post the edited solution in a new post in this thread.
That's preferrable to editing Post #1 itself, which gets very confusing for anybody reading the thread at a later time.
 
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