No problem, glad I could help! :smile:

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Homework Help Overview

The problem involves determining conditions on parameters a and b for a system of linear equations to have no solution, one solution, or infinitely many solutions. The equations are presented in matrix form, and the original poster is exploring the implications of these conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to manipulate the equations into matrix form and reduce them to find solutions. They express confusion regarding the conditions for unique and infinite solutions, particularly seeking clarification on the concept of infinite solutions.

Discussion Status

Participants are engaging with the original poster's attempts, providing hints and guidance without offering complete solutions. There is a productive exchange regarding the understanding of infinite solutions, and some participants confirm the correctness of the original poster's unique solution while encouraging further exploration.

Contextual Notes

The original poster mentions a lack of understanding about infinite solutions and expresses uncertainty about their calculations. There are references to specific conditions (e.g., ab = 2) that lead to no solutions, indicating the need for deeper exploration of these concepts.

Temp0
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Homework Statement


In the following problem, find conditions on a and b such that the system has no solution, one solution, and infinitely many solutions.

x + by = -1
ax + 2y = 5


Homework Equations


None that I know of.


The Attempt at a Solution


Basically, first I put the entire equation into a matrix.
[ 1 b | -1
a 2 | 5 ]
I reduce the bottom by subtracting R2 - aR1
[ 1 b | -1
0 2-ab| 5 +a ]
I then reduce the bottom again by dividing R2/(2-ab)
[ 1 b | -1
0 1 | (5+a)/(2-ab)]
I remove the b from the top by subtraction: R1 - bR2
[1 0 | -1 - b((5+a)/(2-ab))
0 1 | (5+a)/(2-ab) ]
This leaves me with the values for x and y, and for the first question I am correct in saying if ab = 2, then there is no solution as it is undefined. However, my unique solution is somehow wrong and I would like some help in determining if I made an error or I somehow didn't reduce something.

The correct unique solution is: x = (-2 - 5b)/(2-ab) y = (a+5)/(2-ab)

Also, I have no idea what finding an infinite solution means, I would really like some help on clarifying that. Thank you.
 
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Hi Temp0! Welcome to PF! :smile:
Temp0 said:
[1 0 | -1 - b((5+a)/(2-ab))
0 1 | (5+a)/(2-ab) ]

The correct unique solution is: x = (-2 - 5b)/(2-ab) y = (a+5)/(2-ab)

That is the same as yours! :wink:
Also, I have no idea what finding an infinite solution means

Hint: if A and B are two solutions, what can you say about A - B ? :smile:
 
Also, I have no idea what finding an infinite solution means, I would really like some help on clarifying that. Thank you.
For example: if you are given graphs of f(x) and g(x) [neither contain discontinuities] and g(x) 's graph never "falls under" or crosses f(x) , no matter what the argument, g(x) has always higher values than f(x) and you are asked to provide solutions for g(x) > f(x) then you can say that there are infinitely many solutions. But you are dealing with an equal sign so that must mean the 2 graphs are...?
 
tiny-tim said:
Hi Temp0! Welcome to PF! :smile:That is the same as yours! :wink:Hint: if A and B are two solutions, what can you say about A - B ? :smile:

Hmm, thanks for the help on the infinite thing, I finally get that ^^. However, I've tried reducing and expanding my answer, but it never becomes the same as the answer in the book. Are there any hints you can give me? =D

edit: nvm, I just looked at it again and realized how to get to the answer, thanks for your help =p.
 

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