Noether Current: Understanding 2.10 & 2.11

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The discussion focuses on the Noether Current in the context of equations 2.10 and 2.11. It clarifies that the second term in the equation is zero, leading to the conclusion that the change in the Lagrangian, represented as ΔL, can be expressed as α∂μJμ(x). The participant emphasizes that the final equation should indeed reduce to this form, highlighting the separation of the α factor in the context of the Noether theorem. This analysis is crucial for understanding the implications of symmetries in field theory.

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I can't see why the expression gives by the author is right.
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I just don't understand what happened after (2.11). That' is, the second term is zero, so we have
$$\alpha \Delta L = \alpha \partial_{\mu} ( \frac{\partial L}{\partial (\partial_{\mu}\phi)} \Delta \phi )$$
So, second (2.10), isn't ##\Delta L = \alpha \partial_{\mu} J^{\mu}(x)##? So shouldn't the final equation reduce to this?:

##\alpha \alpha \partial_{\mu} J^{\mu}(x) = \alpha \partial_{\mu} ( \frac{\partial L}{\partial (\partial_{\mu}\phi)} \Delta \phi )##
##\partial_{\mu} (\frac{\partial L}{\partial (\partial_{\mu}\phi)} \Delta \phi - \alpha J^{\mu}(x) )##
 
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As defined in 2.11 ##\Delta \mathcal{L} = \partial_\mu \mathcal{J}^\mu##, notice that the ##\alpha## factor is taken into account separatelly.
 

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