Noise Modelling - Digital communication systems

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SUMMARY

The discussion centers on calculating the maximum permitted value of the receiver noise figure in a digital mobile communication system with a noise bandwidth of 200 kHz and an input signal of -104 dBm requiring a minimum SNR of 10 dB. The equation used is FdB = Ps - SNR - 10log(kTB), where the -30 in the equation is identified as a conversion factor between dBW and dBmW. The final calculated noise figure is 6.9 dB.

PREREQUISITES
  • Understanding of digital mobile communication systems
  • Knowledge of signal-to-noise ratio (SNR) calculations
  • Familiarity with dB and dBm conversions
  • Basic grasp of thermal noise calculations using kTB
NEXT STEPS
  • Study the derivation of the noise figure in communication systems
  • Learn about the relationship between dBW and dBm
  • Explore thermal noise calculations in detail, focusing on kTB
  • Investigate the impact of bandwidth on noise figure in digital communications
USEFUL FOR

Students and educators in electrical engineering, particularly those focused on communication systems, as well as professionals involved in designing or analyzing digital mobile communication systems.

CMW328i
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Hi all, Teacher here looking for some guidance. I'm teaching a class that I took myself a few years back, and I'm looking at my solution to a problem but I have a random value in my answer (which I know to be correct) but I can't for the life of me remember where this value came from! Can anyone help?

1. Homework Statement

A receiver in a digital mobile communication system has a noise bandwidth of 200 kHz and requires that its input SNR should be at least 10 dB when the input signal is -104 dBm.
What is the maximum permitted value of the receiver noise figure?2. Homework Equations

FdB = Ps -SNR -10log (kTB)

3. The Attempt at a Solution

FdB = (-104 -30)-10 -10log (1.399x10^-23*290*200000) = 6.9 dBI can't for the life of me figure out where the -30 comes from. I even have an excerpt from the book the question came out of and it just shows the -30 in the equation without explaining where it comes from. Any ideas?

I see the input at -104, I see the bandwith, the required SNR, but no origin for -30
 
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CMW328i said:
Hi all, Teacher here looking for some guidance. I'm teaching a class that I took myself a few years back, and I'm looking at my solution to a problem but I have a random value in my answer (which I know to be correct) but I can't for the life of me remember where this value came from! Can anyone help?

1. Homework Statement

A receiver in a digital mobile communication system has a noise bandwidth of 200 kHz and requires that its input SNR should be at least 10 dB when the input signal is -104 dBm.
What is the maximum permitted value of the receiver noise figure?2. Homework Equations

FdB = Ps -SNR -10log (kTB)

3. The Attempt at a Solution

FdB = (-104 -30)-10 -10log (1.399x10^-23*290*200000) = 6.9 dBI can't for the life of me figure out where the -30 comes from. I even have an excerpt from the book the question came out of and it just shows the -30 in the equation without explaining where it comes from. Any ideas?

I see the input at -104, I see the bandwith, the required SNR, but no origin for -30
Is it a conversion between dB W and dB mW?
 
Ah ha! That may be it actually!
 

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