Find Eb/No : signal to noise ratio

[bos1234]

Homework Statement

If the received signal level for a particular digital system is -151dBw and the receiver system effective noise temperatyre is 1500K, what is E_b/N_o for a link transmitting 2400bps?

solution says:
(Eb/N0) = –151 dBW – 10 log 2400 – 10 log 1500 + 228.6 dBW = 12 dBW

My attempt:
Im trying to use C=Blog_2(1+SNR) and N=kTB
But I have 3 variables and only 2 equations. B's will be canceled but N and SNR(E_b/N_o) are unknown

 

[Rajeswari Rajasingh]

Thermal noise in Watt= kTb
Thermal noise in dBW(N)=10logk +10logT +10logb
N=-228.6+10log1500+10log2400=-163.037dBW
Eb/N0=S/kTb
(Eb/No)dB=S dBW -N dBW=-151 -(-163.037)
=12.03 dBW

 

[berkeman]

Thermal noise in Watt= kTb
Thermal noise in dBW(N)=10logk +10logT +10logb
N=-228.6+10log1500+10log2400=-163.037dBW
Eb/N0=S/kTb
(Eb/No)dB=S dBW -N dBW=-151 -(-163.037)
=12.03 dBW

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