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Homework Help
Calculus and Beyond Homework Help
Non linear pde need to change it to an ode
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[QUOTE="maggie56, post: 3577728, member: 311068"] [h2]Homework Statement [/h2] my non linear pde is du/dt = d/dx [3u[SUP]2[/SUP] - d[SUP]2[/SUP]u/dx[SUP]2[/SUP] ] The question says to let u(x,t) = f(x-ct) Where the function f tends to 0, f' tends to 0 and f'' tends to 0 but the (x-ct) tends to positive or negative infinity. [h2]Homework Equations[/h2] i thought the solution was to find du/dt du/dx d[SUP]2[/SUP]u/dt[SUP]2[/SUP] and d[SUP]2[/SUP]u/dx[SUP]2[/SUP] Which gave me in order as above, -cf' , f' , c[SUP]2[/SUP]f'' , f'' [h2]The Attempt at a Solution[/h2] But when i substitute these into the pde i get -cf' = d/dx[3f[SUP]2[/SUP] - f"] which I am not sure actually helps Could someone please tell me if i am using the correct method or if i have done it completely wrong Thank you [/QUOTE]
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Calculus and Beyond Homework Help
Non linear pde need to change it to an ode
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